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lidiya [134]
3 years ago
10

Which ordered pair is a solution to the equation?

Mathematics
1 answer:
Mama L [17]3 years ago
6 0

Answer:

y=4/5x-3 - (-5, -7)

Step-by-step explanation:

So to solve this, lets just plug in each value for x, and see if the y value we get is equal to one of our answers.

So we have (-10, 5)

Well plug in -10 for 4/5x we get:

-40/5=-8

Next we take that value and solve:

y=-8-3

y=-11

The answer for this was 5, not -11.

Ill skip a few steps:

(10, -11):

Plug in 10 we get:

y=8-3 which is y=5. This is not right, for it needed to be -11.

Next we have (5, -1)

This gets us y=4-3 this is y=1 which is not -1. So thats not right.

Finally we have (-5, -7):

This gets us y=-4-3 this is y=-7. What was our y value? -7!

So the answer is (-5, -7)

I hope this helps! :)

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1. A company has a cash portfolio measured in millions. The drift is 0.1 per month, variance is 0.16per month. The initial cash
Romashka-Z-Leto [24]

Answer:

Step-by-step explanation:

From the information given:

The probability distribution at the end of 6 months is determined as follows:

After 6 months;

Mean of probability distribution =  value of Initial cash  + \alphaT  

=2.0 +(0.1 × 6)

=2.6

After 6 months;

The probability distribution's standard deviation is estimated by using the following formula:

Standard deviation:

=  b\sqrt{T}

= 0.4 \times \sqrt{6}

= 0.9798

Hence, after 6 months;

The company's cash position is supposed to be allocated monthly, with the following expenses.

Mean                            2.6

Standard deviation     0.9798

Variance                      0.96

After 12 months, the probability distribution is as follows:

Mean = value of Initial cash  + \alphaT

= 2.0 +(0.1 × 12)

= 3.2

The standard deviation is:

The standard deviation of probability distribution = b \sqrt{T}

= 0.4 \times \sqrt{12}

= 1.3856

Hence, after 6 months;

The company's cash position is supposed to be allocated monthly, with the following expenses.

Mean                            3.2

Sandard deviation      1.3856

Variance                      1.92

b)  

in 6-month distribution, the probability of the negative value of the cash position is as follows.

Now, for us to find the negative cash distribution;

We need to estimate the z -scores value.

The z-score inform us greatly on the concept of how far a particular data point is from the mean.

For a normal distribution;

z = \dfrac{x-\mu}{\sigma}

Here;

the value of x = zero as a result that if it exceeds zero. the cash position will be negative.

∴

z = \dfrac{x-\mu}{\sigma}

z = \dfrac{0 - 2.6}{0.9798}

z = -2.6536

Using the standard distribution tables, it is now possible to calculate that the likelihood N(-2.65) equals 0.004 or 0.4 percent.

As a result, there's a 0.4 percent chance of getting a negative cash balance after six months.

For 12 months distribution:

The Probability of negative cash position is calculated as follows:

z = \dfrac{x-\mu}{\sigma} \\ \\ z = \dfrac{0-3.2}{1.3856} \\ \\ z = -2.3094

Using the standard distribution tables,

N(-2.31) equals 0.0104 or 1.04 percent.

As a result, there's a 1.04 percent chance of getting a negative cash balance after 1 year  

c) To determine the time period over which the likelihood of achieving a negative cash condition is highest, it's necessary to examine the z-score more closely. Essentially, the z-score measures the difference between a given value(x) and the mean of all potential values (\mu), expressed in terms of the total set's standard deviation (\sigma)

This suggests that the higher the z-score, the greater the difference occurring between x and \mu, and thus the likelihood of receiving x is minimal. As a result, the best chance of finding a certain value is when the z-score is the lowest.

To do so, calculate the derivative of the z-score in relation to the time interval. The point where the derivative is equivalent to zero is where the z-scores are at their lowest.

The first step is to go over the z-score formula in more detail, as seen below.;

z = \dfrac{x-\mu}{\sigma} \\ \\ z = \dfrac{0-(initial \ value + \alpha T)}{b \sqrt{T}} \\ \\ z = \dfrac{-initial \ value }{b\sqrt{T}}-\dfrac{a \sqrt{T}}{b} \\ \\

Now, compute the derivative of this equation with respect to T as follows:

\dfrac{dz}{dT}= \dfrac{initial \ value \times T^{-\dfrac{3}{2}}}{2b} - \dfrac{aT^{-\dfrac{1}{2}}}{2b}

Now, figure out the value of T at which this derivative is equal to zero by substituting all values as follows:

0 = \dfrac{2.0 \times T^{-\dfrac{3}{2}}}{2\times 0.4}- \dfrac{0.1 \times T^{-\dfrac{1}{2}}}{2 \times 0.4} \\ \\  \\ 0.1 \times T^{-\dfrac{1}{2}}= 2.0 \times T^{-\dfrac{3}{2}} \\ \\  \\T = \dfrac{2}{0.1} \\ \\ \\ T = 20

As a result, the time period in which achieving a negative cash condition is = 20 months.

3 0
3 years ago
E Homework: 3.1 Homework
LenKa [72]

The given function is f(z)=3z-8 for the values f(-4), f(2) and f(z-7) respectively -20, -2 and 3z-29 respectively.

The given function is f(z)=3z-8.

We need to find the value of f(-4), f(2), f(z-7).

<h3>What is a function?</h3>

In mathematics, a function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function.

Now to find f(-4), replace z from -4.

f(-4)=3(-4)-8=-12-8=-20

Now to find f(2), replace z from 2.

f(2)=3(2)-8=6-8=-2

Now to find f(z-7), replace z from z-7.

f(z-7)=3(z-7)-8=3z-21-8=3z-29.

Therefore, the given function is f(z)=3z-8 for the values f(-4), f(2) and f(z-7) respectively -20, -2 and 3z-29 respectively.

To learn more about functions visit:

brainly.com/question/21145944.

#SPJ1

4 0
2 years ago
Four friends at a party popped 3/4 of a bag of popcorn. They ate half of what was popped. What fraction of the popcorn in the ba
steposvetlana [31]
Your answer is... they ate 2/4 or 1/2 of the bag of popcorn.
3 0
3 years ago
Show all work to identify the discontinuity and zero of the function f of x equals 4 x over quantity x squared minus 16
Leto [7]

Answer:

Discontinuity of function occurs when x = 4 or x = -4

zero of function is when x=0

Step-by-step explanation:

We are given:

f(x) = \frac{4x}{x^2 - 16}

Discontinuity of the function occur when the denominator is equal to zero.

So, we need to find the values of x that makes the denominator zero.

The denominator is x^2 - 16

x^2 - 16 =0

x^2 = 16

x = ± 4

So, if the value of x = 4 or value of x=-4 then the function will be discontinuous.

Zero of the function i.e f(x)=0

So, Putting the function equal to zero and finding the value of x

\frac{4(x)}{(x)^2 - 16}=0\\4x =0((x)^2 - 16)\\4x=0\\x=0

So, zero of function is when x=0

5 0
3 years ago
Kacie bought x, number of pencils. She paid $0.91, including tax, per pencil. She gave the cashier $10 and received $6.36 back i
wel

Answer:

She purchased 4 pencils

Step-by-step explanation:

Here, we are to calculate the number of pencils bought given the information in the question.

The amount per pencil is $0.91. The total amount of this since she bought x number of pencils is $0.91 * x = $0.91x

Now, after paying $10, she was given $6.36 as change

what this means is that what the pencils cost is 10-6.36 = $3.64

Now we equate the cost in terms of x to this;

0.91x = 3.64

x = 3.64/0.91

x = 4 pencils

4 0
3 years ago
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