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2 years ago

Which ordered pair is a solution to the equation?

Mathematics

1 answer:

Mama L [17]2 years ago

6 0

Answer:

y=4/5x-3 - (-5, -7)

Step-by-step explanation:

So to solve this, lets just plug in each value for x, and see if the y value we get is equal to one of our answers.

So we have (-10, 5)

Well plug in -10 for 4/5x we get:

-40/5=-8

Next we take that value and solve:

y=-8-3

y=-11

The answer for this was 5, not -11.

Ill skip a few steps:

(10, -11):

Plug in 10 we get:

y=8-3 which is y=5. This is not right, for it needed to be -11.

Next we have (5, -1)

This gets us y=4-3 this is y=1 which is not -1. So thats not right.

Finally we have (-5, -7):

This gets us y=-4-3 this is y=-7. What was our y value? -7!

So the answer is (-5, -7)

I hope this helps! :)

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stealth61 [152]

B - f(3) does not exist

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3 years ago

Darina [25.2K]

The graph of the equations was plotted using geogebra graphing and attached.

Let x represent the hours weightlifting and y represent the hours doing cardio exercises.

Since he spend a maximum of 20 hours, hence:

x + y ≤ 20 (1)

Also, he spends at least 8 of those hours weightlifting, hence:

x ≥ 8 (2)

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y ≤ 15 (3)

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2 years ago

Help with thissssssss

kompoz [17]

Answer:

Step-by-step explanation:

1^3 = 1

2^3 = 8

3^3 = 27

4^3 = 64

5^3 = 125

The missing number is 27.

3 0

2 years ago

Read 2 more answers

15 points for someone who can answer & explain this to me thanks

iris [78.8K]

Answer:

see explanation

Step-by-step explanation:

Given

$\frac{9}{a^2+9a+20}$ , $\frac{7a}{a^2+11a+28}$

Factor the denominators of both fractions

$\frac{9}{(a+4)(a+5)}$ , $\frac{7a}{(a+4)(a+7)}$

The lowest common denominator of both fractions is (a + 4)(a + 5)(a + 7)

Multiply numerator/denominator of first fraction by (a + 7)

Multiply numerator/denominator of second fraction by (a + 5 )

$\frac{9(a+7)}{(a+4)(a+5)(a+7)}$ , $\frac{7a(a+5)}{(a+4)(a+5)(a+7)}$ , then

$\frac{9a+63}{(a+4)(a+5)(a+7)}$ , $\frac{7a^2+35a}{(a+4)(a+5)(a+7)}$

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2 years ago

A student ID number is a letter of the alphabet followed by 2 digits. How many different IDs are possible if the digits can be r

mars1129 [50]

First, there are 26 distinct alphabets and 10 distinct digit numbers.

Then, the first digit of ID has 26 possibilities.

For the rest of 2 digits, the total cases are 10*10 = 100 possibilities.

However, there are 10 cases are repeated when two digits are the same. so you have to subtract it by 10

So answer will be 26 * (100-10) = 23400

4 0

2 years ago