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lidiya [134]
3 years ago
10

Which ordered pair is a solution to the equation?

Mathematics
1 answer:
Mama L [17]3 years ago
6 0

Answer:

y=4/5x-3 - (-5, -7)

Step-by-step explanation:

So to solve this, lets just plug in each value for x, and see if the y value we get is equal to one of our answers.

So we have (-10, 5)

Well plug in -10 for 4/5x we get:

-40/5=-8

Next we take that value and solve:

y=-8-3

y=-11

The answer for this was 5, not -11.

Ill skip a few steps:

(10, -11):

Plug in 10 we get:

y=8-3 which is y=5. This is not right, for it needed to be -11.

Next we have (5, -1)

This gets us y=4-3 this is y=1 which is not -1. So thats not right.

Finally we have (-5, -7):

This gets us y=-4-3 this is y=-7. What was our y value? -7!

So the answer is (-5, -7)

I hope this helps! :)

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Reflect AQ'R'S' if Q'(1, -3), R'(-2,-6),<br> and S'(-1,-1) over the x-axis.
castortr0y [4]

Answer:

Step-by-step explanation:

The rule of reflecting over the x-axis is that point (x, y) →( x, -y) so

Q'(1, -3), R'(-2,-6),and S'(-1,-1) reflected over the x-axis, become

Q"(1, 3), R"(-2, 6), and S"(-1, 1) .

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3 years ago
Add. write your answer in simplest form.<br> -4 _/135 + 7 _/15
Zarrin [17]

\huge\quad\qquad\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  - 4 \sqrt{135} + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 4 \sqrt{5 \times3 \times 3 \times 3}  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \:( - 4 \times 3) \sqrt{5 \times 3}  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 12 \sqrt{15 }  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 5 \sqrt{15}

7 0
3 years ago
(x-3)1/3 in its a simplest form
AleksandrR [38]

Answer:  (x-3)/3

Step-by-step explanation:

You have to multiply the fraction.

5 0
4 years ago
alice is writing an essay she has written 774 words there are 9 words on each line how may lines has she written
amid [387]

Answer:

86 words/line

Step-by-step explanation:

774÷9= 86 words

5 0
3 years ago
What is the length of side a? Round to the nearest tenth of an inch. Enter your answer in the box. ( Answer in Inches )
Jet001 [13]

Given:

Base of a right triangle = 7 in

Height of a right triangle = a

Hypotenuse = 16 in

To find:

The length of side a.

Solution:

Using Pythagoras theorem:

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7^{2}+a^{2}=16^{2}

49+a^{2}=256

Subtract 49 from both sides.

49+a^{2}-49=256-49

a^{2}=207

Taking square root on both sides, we get

a = 14.4

The length of side a is 14.4 in.

3 0
3 years ago
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