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viva [34]
3 years ago
11

Which point is an x-intercept of the quadratic function f(x) = (x – 4)(x + 2)? (–4, 0) (–2, 0) (0, 2) (4, –2)

Mathematics
2 answers:
son4ous [18]3 years ago
5 0
<span>f(x) = (x – 4)(x + 2),
x-intercept means that f(x) = 0.

0 = (x-4)(x+2)
(x-4)=0, x= 4, point (4,0)
(x+2)=0, x = -2, point (-2,0)

This graph has 2 x-intercepts:  (4,0) and (-2,0).

From given answers we can choose only </span>(-2,0).
mel-nik [20]3 years ago
3 0

Answer:

The answer is (–2, 0)

I just took the quiz

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let f(x)= p+ 8/x-q. the line x=4 is a vertical asymptote to the graph of f. what is the value of q and p, if the y intercept is
svlad2 [7]

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The value of q and p is 4 and -24  respectively.

Step-by-step explanation:

Being f(x)=\frac{p+8}{x-q} , the line x=4 is a vertical asymptote to the graph of f(x).  The line r is an asymptote of a function if the graph of the function is infinitely close to the line r. That is, an asymptote is a line to which a function approaches indefinitely, without ever touching it.

Being a rational function that which can be expressed as the quotient of two polynomials, a vertical asymptote occurs when the denominator is 0, that is, where the function is not defined. In this case:

x - q= 0

Solving:

x= q

Being the line x=4 the vertical asymptote, then

<u><em>4=q</em></u>

Then the function f (x) is:

f(x)=y=\frac{p+8}{x-4}

The y intercept is (0,4). This is, x= 0 and y=4. Replacing:

4=\frac{p+8}{0-4}

Solving:

4=\frac{p+8}{-4}

4*(-4)= p+8

-16= p+8

-16 - 8= p

<u><em>-24= p</em></u>

<u><em>The value of q and p is 4 and -24  respectively.</em></u>

7 0
3 years ago
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