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2 years ago

Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest

Mathematics

2 answers:

Blababa [14]2 years ago

6 0

Answer:

1/6

Step-by-step explanation:

There are 4 different types of clothing

We want socks

P(socks) = 1/4

Now we have 3 different colors, 2 of which are not blue

P(not blue) =2/3

P(socks that are not blue) = 1/4*2/3 = 2/12 = 1/6

Phoenix [80]2 years ago

6 0

Answer: 1/6

Step-by-step explanation:

There are 4 different types of clothing

We want socks

P(socks) = 1/4

Now we have 3 different colors, 2 of which are not blue

P(not blue) =2/3

P(socks that are not blue) = 1/4*2/3 = 2/12 = 1/6

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Find the midpoint of a line segment with endpoints (4, -10) and (-8, 2).

pychu [463]

Step-by-step explanation: (-2,-4)

5 0

2 years ago

256899 in extended form

Daniel [21]

200000 + 50000 + 6000 + 800 + 90 + 9

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3 years ago

Will mark brainliest if correct (surface area question)

I am Lyosha [343]

Answer:

535

Step-by-step explanation:

8 x 7 = 56

15 x 17 = 255 . 255 / 2 = 127.5

15 x 7 = 105

17 x 7 = 119

119 + 105 + 127.5 + 127.5 + 56 = 535

6 0

2 years ago

Iodine-131 is a radioactive material with half-life of eight days. A scientist starts with 100 grams of iodinie- 131. Which func

MrRissso [65]

The correct answer is Choice A.

This is an example of an exponential equation, so we need the formula $y=ab^x$ .

The a value is the starting value of 100. The b value must be a decimal lower than 1 because it is decreases.

If you substitute in 8 for x, you will see that the output is about 50 (half of 100).

6 0

3 years ago

Read 2 more answers

For 0 ≤ θ < 2 π what are the solutions to sin^2(θ) =2sin^2(θ/2)

gregori [183]

Recall the half-angle identity for sine,

sin²(x/2) = (1 - cos(x))/2

Then the given equation is identical to

sin²(θ) = 1 - cos(θ)

Also recall the Pythagorean identity,

sin²(θ) + cos²(θ) = 1

Then we rewrite the equation as

1 - cos²(θ) = 1 - cos(θ)

Factoring the left side, we have

(1 - cos(θ)) (1 + cos(θ)) = 1 - cos(θ)

and so

(1 - cos(θ)) (1 + cos(θ)) - (1 - cos(θ)) = 0

and we factor this further as

(1 - cos(θ)) (1 + cos(θ) - 1) = 0

which gives

cos(θ) (1 - cos(θ)) = 0

Then either

cos(θ) = 0 or 1 - cos(θ) = 0

cos(θ) = 0 or cos(θ) = 1

[θ = arccos(0) + 2nπ or θ = -arccos(0) + 2nπ]

… or [θ = arccos(1) + 2nπ or θ = -arccos(1) + 2nπ]

(where n is any integer)

[θ = π/2 + 2nπ or θ = -π/2 + 2nπ] or [θ = 0 + 2nπ]

In the interval 0 ≤ θ < 2π, we get three solutions:

• first solution set with n = 0 ⇒ θ = π/2

• second solution set with n = 1 ⇒ θ = 3π/2

• third solution set with n = 0 ⇒ θ = 0

So, the first choice is correct.

6 0

3 years ago