The distance around the outside a circle is its circumference. Consider the formula for the circumference of a circle, Circumference = Pi x Diameter. Solving for Pi we get, Pi = Circumference divided by Diameter.
Answer:
The opponents won by 1 points
Step-by-step explanation:
Your team (10*3)+(8*2)+(12*1)=58
Opponents (8*3)+(12*2)+(11*1)=59
Answer:
let's see what to do...
Step-by-step explanation:
H is between G and I.
G I = G H + H I
38 = 8 x + 7 + 3x - 2
38 = 11 x + 5
subtract the sides of equation minus 5
38 - 5 = 11 x + 5 - 5
33 = 11 x
divided the sides of equation by 11
33 ÷ 11 = 11 x ÷ 11
3 = x
So the lenght of (G H) is :
8 x + 7 -----¢ 8 (3) + 7 = 24 + 7 = 31
And we're done.
Thanks for watching buddy good luck.
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To find the final term to compete the square you need to divide the 'x' term by 2 then square it
- equivalent equation
9514 1404 393
Answer:
a) w(4w-15)
b) w²
c) w(4w -15) = w²
d) w = 5
e) 5 by 5
Step-by-step explanation:
a) If w is the width, and the length is 15 less than 4 times the width, then the length is 4w-15. The area is the product of length and width.
A = w(4w -15)
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b) If w is the side length, the area of the square is (also) the product of length and width:
A = w²
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c) Equating the expressions for area, we have ...
w(4w -15) = w²
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d) we can subtract the right side to get ...
4w² -15w -w² = 0
3w(w -5) = 0
This has solutions w=0 and w=5. Only the positive solution is sensible in this problem.
The side length of the square is 5 units.
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e) The rectangle is 5 units wide, and 4(5)-15 = 5 units long.
The rectangle and square have the same width and the same area, so the rectangle must be a square.
