Answer:
D 4,3,2
Explanation:
4 Co + 3 O2 ----> 2 Co2O3
Answer:
The answer to your question is V = 19.9 L
Explanation:
Data
mass of Al = 8.60 g
volume of H₂ = ?
Balanced chemical reaction
2Al + 6HCl ⇒ 2AlCl₃ + 3H₂
1.- Use proportions to calculate the mass of H₂ produced
Atomic mass of Al = 2 x 27 = 54 g
Atomic mass of H₂ = 6 x 1 = 6 g
54 g of Al -------------------- 6 g of H₂
8 g of Al ------------------- x
x = (8 x 6) / 54
x = 48 / 54
x = 0.89 g of H₂
2.- Calculate the volume of H₂
- Convert the H₂ to moles
1 g of H₂ --------------- 1 mol
0.89 g ---------------- x
x = 0.89 moles
1 mol of H₂ -------------- 22.4 l
0.89 moles ------------- x
x = (0.89 x 22.4) / 1
x = 19.9 L
<span>atomic weights: Al = 26.98, Cl = 35.45
In this reaction; 2Al = 53.96 and 3Cl2 = 212.7
Ratio of Al:Cl = 53.96/212.7 = 0.2537 that is approximately four times the mass Cl is needed.
Step 2:
(a) Ratio of Al:Cl = 2.70/4.05 = 0.6667
since the ratio is greater than 0.2537 the divisor which is Cl is not big enough to give a smaller ratio equal to 0.2537.
so Cl is limiting
(b)since Cl is the limiting reactant 4.05g will be used to determine the mass of AlCl3 that can be produced.
From Step 1:
212.7g of Cl will produce 266.66g AlCl3
212.7g = 266.66g
4.05g = x
x = 5.08g of AlCl3 can be produced
(c)
Al:Cl = 0.2537
Al:Cl = Al:4.05 = 0.2537
mass of Al used in reaction = 4.05 x 0.2537 = 1.027g
Excess reactant = 2.70 - 1.027 = 1.67g
King Leo · 9 years ago</span>
