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icang [17]
3 years ago
14

How do I find the Axis of Symmetry for a parabola

Mathematics
2 answers:
oee [108]3 years ago
7 0

Answer:

The equation of the axis of symmetry of the parabola is x = h,

 where h is the x-coordinate of the vertex point

Step-by-step explanation:

* The axis of symmetry is the line which divides the

 shape into two congruent parts

* The general form of the quadratic equation is:

 ax² + bx + c = 0

* The quadratic equation is represented graphically by parabola

∵ The parabola has minimum point or maximum point

∴ The axis of symmetry of the parabola is passing through this point

   This point is called the vertex point or the turning point

- Lets find this point:

* the x-coordinate of this point calculated from the equation

 x- coordinate of the vertex point h = -b/2a

- where b is the coefficient of x and a is the coefficient of x²

∴  The equation of the axis of symmetry of the parabola is x = -b/2a

EX:

- If ⇒ x² - 4x + 4 = 0

∵ a = 1 , b = -4

∴ h = -(-4)/2(1) = 2

∴ The equation of the axis of symmetry of the parabola is x = 2

The graph show you the axis of symmetry

soldier1979 [14.2K]3 years ago
4 0

Answer:

Explanation given below.

Step-by-step explanation:

The first step is to put the parabola in the form  ax^2+bx+c , which is the <em>standard form of a parabola</em>

<em />

<u>Note:</u> a is the coefficient before x^2 term, b is the coefficient before x term, and c is the independent constant term

The axis of symmetry divides the parabola symmetrically. The axis of symmetry has the equation  x=-\frac{b}{2a}

Where <em><u>a and b are the respective values shown above</u></em>

<em><u /></em>

So, that is how you get the axis of symmetry of any parabola.

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X/2 = Y/3 = Z/4. prove that :2X-Y+5Z / 3Y-X =3. note :: (/) is for a fraction aka divide. help pls I've been stuck on it for a f
sweet-ann [11.9K]

The given equation

x/2 = y/3 = z/4

can be broken into three separate equations which I'll call equations (A), (B) and (C)

  • x/2 = y/3 ..... equation (A)
  • y/3 = z/4 .... equation (B)
  • x/2 = z/4 .... equation (C)

We'll start off solving for z in equation (C)

x/2 = z/4

4x = 2z ... cross multiply

2z = 4x

z = 4x/2 ... divide both sides by 2

z = 2x

Now let's solve for y in equation (A)

x/2 = y/3

3x = 2y

2y = 3x

y = 3x/2

y = (3/2)x

y = 1.5x

The results of z = 2x and y = 1.5x both have the right hand sides in terms of x. This will allow us to replace the variables y and z with something in terms of x, which means we'll have some overall expression with x only. The idea is that expression should simplify to 3 if we played our cards right.

We won't be using equation (B) at all.

---------------------

The key takeaway from the last section is that

  • z = 2x
  • y = 1.5x

Let's plug those items into the expression (2x-y+5z)/(3y-x) to get the following:

(2x-y+5z)/(3y-x)

(2x-y+5(2x))/(3y-x) ..... plug in z = 2x

(2x-y+10x)/(3y-x)

(12x-y)/(3y-x)

(12x-1.5x)/(3(1.5x)-x) .... plug in y = 1.5x

(12x-1.5x)/(4.5x-x)

(10.5x)/(3.5x)

(10.5)/(3.5)

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We've shown that plugging z = 2x and y = 1.5x into the expression above simplifies to 3. Therefore, the equation (2x-y+5z)/(3y-x) = 3 is true when x/2 = y/3 = z/4. This concludes the proof.

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From the graph attached,

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