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d1i1m1o1n [39]
3 years ago
8

1. y > 2x + 3 graph it, 2. 3x + y = 4 and x - y = 0, solve for x.

Mathematics
1 answer:
kirza4 [7]3 years ago
8 0

Answer:

  1. see the attachment
  2. (x, y) = (1, 1)

Step-by-step explanation:

1. Since you have y > ..., the boundary line is dashed and the shading is above it (for y-values greater than the values on the line). The boundary line is ...

  y = 2x+3

which has a y-intercept of 3 and a slope (rise/run) of 2. A graph is attached.

__

2. You can add the two equations to eliminate y:

  (3x +y) +(x -y) = (4) +(0)

  4x = 4

  x = 1

  1 - y = 0 . . . . substitute into the the second equation

  1 = y . . . . . . . add y

The solution is (x, y) = (1, 1).

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<span>y + 4 ≤ 0
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Find the equation of the quadratic function with vertex (-2,18) passing through (-5,0)?
Sliva [168]

Answer:

y-18=-2(x+2)^2

Step-by-step explanation:

Equation of the Quadratic Function

The vertex form of the quadratic function has the following equation:

y-k=a(x-h)^2

Where (h, k) is the vertex of the parabola that results when plotting the function, and a is a coefficient different from zero.

It's been given the vertex of the parabola as (-2,18):

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Now substitute the point (-5,0) and find the value of a:

0-18=a(-5+2)^2

Operating:

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Solving for a:

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2 years ago
How to sovle <br> (x+1/x)^2
Slav-nsk [51]

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Hope you could get an idea from here.

Doubt clarification- use comment section.

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Answer:

3b \geq -22

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