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8_murik_8 [283]
4 years ago
5

Two large metal plates of area 0.7 m2 face each other. They are 5.1 cm apart and have equal but opposite charges on their inner

surfaces. If the magnitude E of the electric field between the plates is 55 N/C, what is the magnitude of the charge on each plate? Neglect edge effects.
Physics
1 answer:
german4 years ago
8 0

Explanation:

The given data is as follows.

    Area (A) = 0.7 m^{2}.

  Electric field between the plates, (E) = 55 N/C

Since, electric field is related to surface charge density as follows.

          \sigma = \frac{Q}{A}

Also,    E = \frac{\sigma}{\epsilon_{o}}

or,        \sigma = \epsilon_{o} E

Therefore, charge will be calculated as follows.

          Q = \sigma \times A = \epsilon_{o} E \times A

             = 8.854 \times 10^{-12} \times 55 \times 0.7

             = 3.41 \times 10^{-10} C

             = 341 pC

Thus, we can conclude that magnitude of the charge on each plate is 341 pC.

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