To solve this problem it is necessary to apply the concepts related to the continuity of fluids in a pipeline and apply Bernoulli's balance on the given speeds.
Our values are given as


From the continuity equations in pipes we have to

Where,
= Cross sectional Area at each section
= Flow Velocity at each section
Then replacing we have,



From Bernoulli equation we have that the change in the pressure is

![7.3*10^3 = \frac{1}{2} (1000)([ \frac{(1.25*10^{-2})^2 }{0.6*10^{-2})^2} v_1 ]^2-v_1^2)](https://tex.z-dn.net/?f=7.3%2A10%5E3%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%281000%29%28%5B%20%5Cfrac%7B%281.25%2A10%5E%7B-2%7D%29%5E2%20%7D%7B0.6%2A10%5E%7B-2%7D%29%5E2%7D%20v_1%20%5D%5E2-v_1%5E2%29)


Therefore the speed of flow in the first tube is 0.9m/s
Answer:
A: 0.83 Hz
Explanation:
Frequency can be calculated in a multitude of ways. The one way that is going to help you solve this problem is (# of times/seconds)
so you would divide 85 swings/102 seconds
= 5/6 or 0.8333 Hz
so your answer is A
Answer:
P = 9800 [Pa]
Explanation:
In order to calculate the pressure at the bottom, we must use the following formula.
P = Ro*g*h
where:
P = pressure [Pa] (units of pascals)
Ro = density of the water = 1000 [kg/m³]
g = gravity acceleration = 9.8 [m/s²]
h = height = 1 [m] (because its half of the portion, the full height is 2 m)
P = 1000*9.8*1
P = 9800 [Pa]
Answer is C is the correct answer
Answer:
F = 263.51 N
Explanation:
given,
diameter of wheel = 78 cm
diameter of axle = 14.8 cm
Force exerted on the rim of wheel = 150 N
Force applied outside the axle = ?
To prevent rotation wheel from rotating the Force 'F' should be applied outside of the axle.
Net momentum about the center of mass should be zero
now,
Moment of about center due to 150 N = moment about center due to F on axle

7.4 F = 1950
F = 263.51 N
Hence, Force exerted outside of the axle in order to prevent the wheel from rotating is equal to 263.51 N.