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jarptica [38.1K]
3 years ago
5

If an object is rolling without slipping, how does its linear speed compare to its rotational speed? If an object is rolling wit

hout slipping, how does its linear speed compare to its rotational speed? v = Rω v = ω/R They are unrelated. v = ω
Physics
1 answer:
salantis [7]3 years ago
6 0

Answer:

v = r\omega

Explanation:

If the object is rolling without slipping, every unit of rotated angle equals to a distance perimeter rotated.

Suppose the object complete 1 revolution within time t. The angular distance is 2π rad. Its angular velocity is 2π/t

The distance it covered is its circumference, which is 2πr, and so the speed is 2πr/t

So the linear speed compared to angular speed is

\frac{v}{\omega} = \frac{2\pi r/t}{2\pi /t} = r

v = r\omega

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Murrr4er [49]

I'm not sure that's true ... we'd need to see some numbers.
But if it is true, it's the same reason why some places don't
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Pressure is        (weight) divided by (area).

Pressure exerted
by a ballerina      =    (ballerina's weight)/(area of her toe on the floor)

Pressure exerted
by an elephant    =    (elephant's weight)/(area of 4 elephant feet)

Pressure exerted by
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You can see that the greatest weight might not exert the greatest
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Baking soda is often used in experiments to neutralize vinegar. In the picture above, the beaker on the left contains a solution
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It must be a base since it has the opposite reaction to litmus paper as vinegar and vinegar is an acid  
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6 0
3 years ago
A batter hits a ball at 35 degrees above the horizontal and it is caught 4 seconds later 100 meters from home plate. What is the
Mamont248 [21]

Answer:

u=(26.5 i + 18.5j) m/s

Explanation:

The range of a projectile is given by the formula

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where in this case, we have

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Solving for u, we find:

u=\sqrt{\frac{dg}{sin 2\theta}}=\sqrt{\frac{(100)(9.8)}{sin(2\cdot 35^{\circ})}}=32.3 m/s

Now we can easily find the components of the initial velocity:

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So, the initial velocity of the ball is

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