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Aleonysh [2.5K]
3 years ago
10

On the bottom right corner. I need help on that please! First to answer gets branliest and

Mathematics
1 answer:
katen-ka-za [31]3 years ago
6 0

Answer:

20%×60

1/5×60

i only help these two

Step-by-step explanation:

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Find a quadratic expression with integer coefficients whose roots are <img src="https://tex.z-dn.net/?f=5%2F2%2B%203i" id="TexFo
prohojiy [21]

Answer:

4x² -20x  +61

Step-by-step explanation:

the quadratic equation can be written as (x-root1)(x-root2)

(x-(5/2) -3i) (x-(5/2)+3i), distribute

x² -(5/2)x +3xi -(5/2)x + 25/4 -(15/2)i -3xi +(15/2)i -9i², simplify

x² -(5/2)x -(5/2)x + 25/4  -9i², use the fact that i² =(√-1)² = -1 and substitute i²

x² -(5/2)x -(5/2)x + 25/4 +9, combine like terms and rewrite 9 as 36/4

x² -(10/2)x  +25/4 + 36/4, combine like terms and simplify

x² -5x  +61/4 is the quadratic expression yet it does not have integer coefficients so multiply by 4 to have all coefficients integers

4x² -20x  +61

7 0
3 years ago
Let the number of chocolate chips in a certain type of cookie have a Poisson distribution. We want the probability that a cookie
ludmilkaskok [199]

Answer:

\lambda \geq 6.63835

Step-by-step explanation:

The Poisson Distribution is "a discrete probability distribution that expresses the probability of a given number of events occurring in a fixed interval of time or space if these events occur with a known constant mean rate and independently of the time since the last event".

Let X the random variable that represent the number of chocolate chips in a certain type of cookie. We know that X \sim Poisson(\lambda)

The probability mass function for the random variable is given by:

f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...

And f(x)=0 for other case.

For this distribution the expected value is the same parameter \lambda

E(X)=\mu =\lambda

On this case we are interested on the probability of having at least two chocolate chips, and using the complement rule we have this:

P(X\geq 2)=1-P(X

Using the pmf we can find the individual probabilities like this:

P(X=0)=\frac{e^{-\lambda} \lambda^0}{0!}=e^{-\lambda}

P(X=1)=\frac{e^{-\lambda} \lambda^1}{1!}=\lambda e^{-\lambda}

And replacing we have this:

P(X\geq 2)=1-[P(X=0)+P(X=1)]=1-[e^{-\lambda} +\lambda e^{-\lambda}[]

P(X\geq 2)=1-e^{-\lambda}(1+\lambda)

And we want this probability that at least of 99%, so we can set upt the following inequality:

P(X\geq 2)=1-e^{-\lambda}(1+\lambda)\geq 0.99

And now we can solve for \lambda

0.01 \geq e^{-\lambda}(1+\lambda)

Applying natural log on both sides we have:

ln(0.01) \geq ln(e^{-\lambda}+ln(1+\lambda)

ln(0.01) \geq -\lambda+ln(1+\lambda)

\lambda-ln(1+\lambda)+ln(0.01) \geq 0

Thats a no linear equation but if we use a numerical method like the Newthon raphson Method or the Jacobi method we find a good point of estimate for the solution.

Using the Newthon Raphson method, we apply this formula:

x_{n+1}=x_n -\frac{f(x_n)}{f'(x_n)}

Where :

f(x_n)=\lambda -ln(1+\lambda)+ln(0.01)

f'(x_n)=1-\frac{1}{1+\lambda}

Iterating as shown on the figure attached we find a final solution given by:

\lambda \geq 6.63835

4 0
3 years ago
SHAYNA FREEL PLANS TO BUY $17.45 WORTH OF STATIONERY SUPPLIES. IF THE SALES TAX IS 13%, HOW MUCH WILL SHAYNA PAY?
Rainbow [258]

9514 1404 393

Answer:

  $19.72

Step-by-step explanation:

The sales tax is 13% of $17.45:

  0.13 × $17.45 = $2.27 . . . . . . rounded (up) to the nearest cent

Then the total Shayna will pay is ...

  $17.45 +2.27 = $19.72

7 0
3 years ago
Wanna hear something funny I have been asking questions about math all day but none of them have been answered like this is the
scZoUnD [109]

Answer:

lollllllll

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Koto’s average velocity along her route was 4. 5 m/s. She started at her house and traveled 15,000 meters north, 5,000 meters ea
Lostsunrise [7]

The time taken for her trip is 3 hours.

<h3>Given that</h3>

Koto’s average velocity along her route was 4. 5 m/s.

She started at her house and traveled 15,000 meters north, 5,000 meters east, 20,000 meters south, and then 5,000 meters west.

<h3>We have to determine</h3>

What was the time of her trip?

<h3>According to the question</h3>

She started at her house and traveled 15,000 meters north, 5,000 meters east, 20,000 meters south, and then 5,000 meters west.

<h3 /><h3>The calculation of such a trip of Koto can be done by applying the known formula of Time when the Speed is multiplied by Distance to compute the actual time of the trip.</h3>

The formula to calculate the time for her trip is;

\rm Speed = \dfrac{ Distance}{Time}\\&#10;\\&#10;Time = \dfrac{Distance}{Speed}\\&#10;\\&#10;

  • Using the formula above, the commute in each direction is added as 45000 meters or 45 kilometers.

  • If Koto's average speed is 4.5 meters per second, then she travels roughly 270 meters in one minute.

Substitute all the values in the formula;

\rm\ Time = \dfrac{Distance}{Speed}\\\\  Time = \dfrac{45000}{270}\\&#10;\\&#10;Time =166.7

Converting minutes into hours,

\rm Hours = \dfrac{Minute}{60}\\&#10;\\&#10;Hours = \dfrac{166.7}{60}\\&#10;\\&#10;Hours = 2.77 \\&#10;\\&#10;= 3\  hours

Hence, the time taken for her trip is 3 hours.

To know more about Time and Distance click the link given below.

brainly.com/question/4433818

5 0
2 years ago
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