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Slav-nsk [51]
4 years ago
13

What is the sequence of transformations that maps abc to a’b’c’ ?

Mathematics
1 answer:
JulsSmile [24]4 years ago
5 0

Answer:

In Step 1: option D is correct

And in step 2: option A is correct.

Step-by-step explanation:

We have been given the graph

The figure in fourth quadrant after rotating 90 degrees counterclockwise about the origin will shift in first quadrant.

And after translating 4 units left will give the figure shown in second quadrant.

Therefore, In Step 1: option D is correct

And in step 2: option a is correct.

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elena-s [515]
1.31779e14 is the answer to your question
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3 years ago
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What is the slope-intercept for equation for the line that passes through (1,3) and (3,7)?
marusya05 [52]
Slope -intercept form is
y = 2x + 1 \:  \:  \:  \:  \: or \: just \: y = 2x

4 0
4 years ago
What is the product? startfraction 4 k 2 over k squared minus 4 endfraction times startfraction k minus 2 over 2 k 1 endfraction
Tcecarenko [31]

The product of the expression (\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1}  is the expression \frac{2}{k+2}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the expression:

(\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1} \\\\This\ can\ be\ simplified\ to:\\\\(\frac{2(2k+1)(k-2)}{(k+2)(k-2)(2k+1)}) \\\\=\frac{2}{k+2}

The product of the expression (\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1} is the expression \frac{2}{k+2}

Find out more on equation at: brainly.com/question/2972832

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7 0
3 years ago
Question A volleyball team sold raffle tickets to raise money for the upcoming season. They sold three different types of ticket
m_a_m_a [10]

Answer:

24 premium tickets were sold.

Step-by-step explanation:

Let :

Deluxe ticket = x

Regular tickets = x + 78

Premium tickets = y

x + (x + 78) + y = 208

4x + 2(x+78) + 10y = 714

2x + y = 208 - 78

4x + 2x + 156 + 10y = 714

2x + y = 130 - - - - - (1)

6x + 10y = 558 - - - - (2)

Now we can solve the simultaneous equation using elimination method :

From (1)

y = 130 - 2x

Put y = 130 - 2x in (2)

6x + 10(130 - 2x) = 558

6x + 1300 - 20x = 558

- 14x = 558 - 1300

-14x = - 742

x = 742 / 14

x = 53

Put x = 53 in y = 130 - 2x

y = 130 - 2(53)

y = 130 - 106

y = 24

3 0
3 years ago
Can someone help me please
Andrej [43]
It would be D because the equation just seems flipped, but the requirements of x are fulfilled.
3 0
3 years ago
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