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zmey [24]
3 years ago
6

Please help I have an exam tomorrow!!!!

Mathematics
1 answer:
Zepler [3.9K]3 years ago
5 0
I think the most appropriate answer would be "-6.58".

I hope it helped you!
You might be interested in
The length of a rectangle is 5 inches less than twice its width. The perimeter of the rectangle is 26 inches. What is the width
Yakvenalex [24]

Answer:

w= 6

Step-by-step explanation:

I just started by making an educated guess using the values already given. Then I inserted that into the problem to see if it worked.

L= 2w - 5

I used 6 as a random, educated guess for the value of w.

L = 2(6) - 5

L = 12-5

L = 7

Then, multiply L by 2 to account for both side lengths of the rectangle.

7(2)= 14

Subtract that value from the total perimeter to find what the width must equal.

26 - 14 = 12

Divide that answer by 2 since there are two sides for width.

12/2 = 6

I know this was kind of long, but I hope it helps! :)

3 0
3 years ago
3 2/3 x 1/5= please help
Nonamiya [84]

Answer: 11/15

Step-by-step explanation:

6 0
3 years ago
Based on the information below, choose the correct answers.
lozanna [386]

Since there are 120 payment and the total interest paid was $ 14,644.95. so the average monthly interest can be calculated by:

Average monthly interest = $ 14,644.95 / 120

Average monthly interest = $ 122.04

 

% total interest = ($ 14,644.95) / $ 39,644.95 x 100

% total interest =36.94 %

8 0
3 years ago
On a coordinate plane, the x-axis is labeled bags of trail mix and the y-axis is labeled ounces of almonds. Line a is labeled y
Musya8 [376]

Answer:

Line B

Step-by-step explanation:

Only one line on the graph shows 2 ounces of almonds for 1 bag of trail mix: line B.

7 0
3 years ago
Read 2 more answers
Use the following matrices, A, B, C and D to perform each operation.
Vinvika [58]

Step-by-step explanation:

A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]

B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]

C=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]

D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]

1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]

2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]

3.\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]

4.\\C\cdot D=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\cdot\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\=\left[\begin{array}{ccc}7&-8&-6\\14&13&-8\end{array}\right]

5.\\2D+3C\\\text{This operation can't be performed because the matrices}\\\text{ are of different dimensions.}

6 0
3 years ago
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