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photoshop1234 [79]
2 years ago
8

An object is thrown upward from the top of 96​-foot building with an initial velocity of 80 feet per second. The height h of the

object after t seconds is given by the quadratic equation h=16t^2+80t+96. When will the object hit the​ ground?
Mathematics
1 answer:
stiks02 [169]2 years ago
5 0

The function of the object height is an illustration of a projectile motion

The object will never hit the ground

<h3>How to determine when the object hits the ground?</h3>

The function is given as:

h=16t^2+80t+96.

When the object hits the ground, h = 0

So, we have:

16t^2+80t+96 = 0

Divide through by 16

t^2+5t+6 = 0

Expand

t^2 + 3t + 2t + 6 = 0

Factorize

t(t + 3) + 2(t + 3) = 0

Factor out t + 3

(t + 2)(t + 3) = 0

Solve for t

t = -2 or t = -3

The time (t) cannot be negative.

Hence, the object will never hit the ground

Read more about projectile motion at:

brainly.com/question/1130127

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Tammy’s home cost her $184,000. She lives in an area with a lively real estate market, and her home increases in value by 3. 5
garri49 [273]

The profit to be made when she sells the house is $103,800.

The first step is to determine the value of Tammy's house in 13 years. The formula to be used is:

  • FV = P (1 + r)^n
  • FV = Future value  
  • P = Present value  
  • R = interest rate  
  • N = number of years  

$184,000 x (1.035)^13 = $287,767.92

Profit = value of the house in 13 years - cost of the house

$287,767.92 - $184,000 = 103,767 = $103,800

To learn more about future value, please check: brainly.com/question/18760477

5 0
3 years ago
WILL GIVE BRAINLIEST
12345 [234]

Answer:

Step-by-step explanation:

it is an arithmetic sequence.

c=6-3=3

\[a_{n}=3+(n-1)*3\]

\a_{n}=3n

a_{8}=3*8=24

8 0
3 years ago
Identify the phase shift of each function. Describe each phase shift ( use a phrase like 3 units to the left):
Temka [501]
ANSWER

Phase shift: 2 units right.

EXPLANATION

The given sine function is

y = - \sin(x - 2)

In mathematics, a horizontal shift may also be referred to as the phase shift.

This function is shifted to the right 2 units.
8 0
3 years ago
A local bagel shop produces two products: bagels (B) and croissants (C). Each bagel requires 6 ounces of flour, 1 gram of yeast,
KengaRu [80]

Answer:

  see below

Step-by-step explanation:

If we let X represent the number of bagels produced, and Y the number of croissants, then we want ...

(a)   Max Profit = 20X +30Y

(b)   Subject to ...

     6X +3Y ≤ 6600 . . . . . . available flour

     X + Y ≤ 1400 . . . . . . . . available yeast

     2X +4Y ≤ 4800 . . . . . . available sugar

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Production of 400 bagels and 1000 croissants will produce a maximum profit of $380.

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In the attached graph, we have shaded the areas that are NOT part of the solution set. (X and Y less than 0 are also not part of the solution set, but are left unshaded.) This approach can sometimes make the solution space easier to understand, since it is white.

The vertex of the solution space that moves the profit function farthest from the origin is the one we are seeking. The point that does that is (X, Y) = (400, 1000).

4 0
3 years ago
Evaluate the expression.<br> (15 + 6) divided by 3
pshichka [43]
7. (15+6)=21 and 21/3=7
3 0
3 years ago
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