Checking the <span>discontinuity at point -4
from the left f(-4) = 4
from the right f(-4) = (-4+2)² = (-2)² = 4
∴ The function is continues at -4
</span>
<span>Checking the <span>discontinuity at point -2
from the left f(-2) = </span></span><span><span>(-2+2)² = 0
</span>from the right f(-2) = -(1/2)*(-2)+1 = 2
∴ The function is jump discontinues at -2
</span>
<span>Checking the <span>discontinuity at point 4
from the left f(4) = </span></span><span><span>-(1/2)*4+1 = -1
</span>from the right f(4) = -1
but there no equality in the equation so,
</span><span>∴ The function is discontinues at 4
The correct choice is the second
point </span>discontinuity at x = 4 and jump <span>discontinuity at x = -2</span>
The inequality is 8-1/4x>27. The solution of the inequality is b<-76.
Given that,
The inequality is 8-1/4x>27
We must determine how to address the inequity.
Take,
8-1/4x>27
Multiply the inequality's two sides by its lowest common denominator,
4×8-4×1/4b>27×4
Reduce the expression to the lowers term,
4×8-b>4×27
Calculate the product or quotient,
32-b>4×27
Calculate the product or quotient,
32-b>108
Rearrange unknown terms to the left side of the equation,
-b>108-32
Calculate the sum or difference,
-b>76
Divide the inequality's two sides by the variable's coefficient,
b<-76
Therefore, the solution of the inequality is b<-76.
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The graph represents a function but the table does not. The reason for this is that one input value (70) in the table is associated with two output values (54.6 and 53.11), which is a sure sign that we do NOT have a function here.
Answer:
Step-by-step explanation:
Given:
u = 1, 0, -4
In unit vector notation,
u = i + 0j - 4k
Now, to get all unit vectors that are orthogonal to vector u, remember that two vectors are orthogonal if their dot product is zero.
If v = v₁ i + v₂ j + v₃ k is one of those vectors that are orthogonal to u, then
u. v = 0 [<em>substitute for the values of u and v</em>]
=> (i + 0j - 4k) . (v₁ i + v₂ j + v₃ k) = 0 [<em>simplify</em>]
=> v₁ + 0 - 4v₃ = 0
=> v₁ = 4v₃
Plug in the value of v₁ = 4v₃ into vector v as follows
v = 4v₃ i + v₂ j + v₃ k -------------(i)
Equation (i) is the generalized form of all vectors that will be orthogonal to vector u
Now,
Get the generalized unit vector by dividing the equation (i) by the magnitude of the generalized vector form. i.e
Where;
|v| = 
|v| = 
= 
This is the general form of all unit vectors that are orthogonal to vector u
where v₂ and v₃ are non-zero arbitrary real numbers.
Answer:
r=9/2 or 4.5
Step-by-step explanation:
First of all our goal is to get R by itself
by cross multiplying we get,
(r+3)*3=5r
by distributive property we get
3r+9=5r
substracting 3r from both sides we get
9=2r
by dividing by 2 in both sides we get
r=9/2 or 4.5
