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krek1111 [17]
3 years ago
14

-3 (5 g +1) + 8 g

Mathematics
1 answer:
Komok [63]3 years ago
8 0

Answer:

-7g-3

Step-by-step explanation:

in order to evaluate for this mathematical expression, we need to consider the negative sign carefully and then open the bracket then evaluate.

<u>solutuion</u>

-3 (5 g +1) + 8 g

-15g -3 + 8g

-15g +8g -3

-7g-3

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Svet_ta [14]

Answer:

(-8) + (-8) + (-8) + (-8)

Step-by-step explanation:

Since Yan is descending ; we represent his movement as being negative.

Number of rungs descended before stopping = 4

Number of stops = 8

Given that no extra steps was taken ;

Number of ladder rungs descended :

4 rungs per stop for 8 stops

- 4 * 8 = - 32 rungs

Another way to write the product :

Number of stops added in number of rungs descended :

(-8) + (-8) + (-8) + (-8)

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3 years ago
Aria is a songwriter who collects royalties on her songs whenever they are played in a
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Answer:

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Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
-1/6 + 2/3 ( 9 + - 3/4) + - 1/2
Liono4ka [1.6K]
First simplify the section in the parenthesis. 
-1/6 + 2/3(8 1/4) + -1/2 
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-1/6 + 5 1/2 + -1/2 
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7 0
3 years ago
(PLEASE HELP) The table below - does it represent an exponential function?
Aliun [14]
Short answer: I don't know, but that doesn't mean I can't give you something that you can decide for yourself.
y = 4*2^(2n - 2) is the pattern.
Go for broke. Try n = 4. You should get 256. Let's try it.
y = 4 * 2^(2*4 - 2)
y = 4 * 2^(8 - 2)
y = 4 * 2^6
y = 4 * 64
y = 256 yup it works.

The other end is just as important. Suppose n = 1
Then y = 4 * 2^(2*1 - 2) = 4 * 2^0 = 4*1 = 4 Both work.

If this formula is correct, we can abbreviate it to make your task easier.
y = 4 * 2^(2n - 2)
y = 2^2 * 2^(2n - 2)
y = 2^(2n - 2 + 2)
y = 2^(2n) Now try the two end points again.

n = 4
y = 2^(2*4)
y  =  2^8
y = 256

n = 1
y = 2^(2*1)
y = 2^2
y = 4 which again checks.

so y = 2^(2n) I think is an exponential function.
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4 years ago
An evaluation of the habitats of endangered salmon species was performed in Conservation Ecology (December 2003). The researcher
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Step-by-step explanation:

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