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Vika [28.1K]
2 years ago
5

Help with 5 and 6 please

Mathematics
1 answer:
nirvana33 [79]2 years ago
5 0
Number 5 is 166cm and number 6 is 68yd.
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−2(2x+3)≤26<br><br>-<br><br>2<br><br>2<br><br>x<br><br>+<br><br>3<br><br>≤<br><br>26<br><br>?
SashulF [63]

\huge \boxed{\mathbb{QUESTION} \downarrow}

- 2 ( 2 x + 3 ) \leq 26.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

- 2 ( 2 x + 3 ) \leq 26

Divide both sides by -2. We know that since 2 is negative, it'll be < (less than) 0. So, the direction of inequality will change.

2x+3\geq \frac{26}{-2}  \\

Divide 26 by -2..we'll get the answer as -13.

2x+3\geq -13

Now, subtract 3 from both the sides.

2x\geq -13-3

Subtracting -13 by 3..we'll get the answer as -16.

2x\geq -16

Divide both sides by 2. We know that since 2 is positive, the direction of inequality will remain the same.

x\geq \frac{-16}{2}  \\

Divide -16 by 2..we'll get the answer as -8.

\huge \boxed{ \boxed{ \bf \: x\geq -8 }}

  • The correct answer is ⇨ <u>x </u><u>greater </u><u>than </u><u>or </u><u>equal</u><u> to</u><u> </u><u>-</u><u>8</u><u>.</u>
3 0
2 years ago
The diagram shows a cube with sides of length 8 meters. A smaller cube with
Tanya [424]

Answer:

a) 512 cm^3

b) 469.125 cm^3

Step-by-step explanation:

8*8*8 = 512 cm^3

or

8^3 = 512 cm^3

3.5^3 = 42.875

512 - 42.875 = 469.125 cm^3

You can round the second answer down

5 0
2 years ago
What is the equation of the line that passes through the point (3,-3) and has a slope of 0?
Blizzard [7]

Answer:

given us,

slope= 0

(x1y1)= (3,-3)

here

(y-y1) =m(x-x1)

or, (y+3)=0(x-3)

or (y+3)= x-3

or, x+y= -3-3

x+y= -6

Step-by-step explanation:

x+y= -6

7 0
3 years ago
How many steps are there in the problem-solving process
Alex73 [517]

Answer:

Step-by-step explanation: There are four steps

8 0
3 years ago
Frank had 42 rocks that he wanted to share with his friends. If he gave each friend the same number of rocks(and kept the same n
shutvik [7]

Answer:6. 42 split 7 ways is 6

Step-by-step explanation:

7 0
2 years ago
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