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3 years ago

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Engineering

1 answer:

masha68 [24]3 years ago

4 0

Ummmmmmm do u need help with anything ✌?

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What are the general principles of DFA? What are the steps to minimize the number of parts for an assembly?

BigorU [14]

Answer Explanation : The general principles for design for assembly (DFA) are,

MINIMIZE NUMBER OF COMPONENT
USE STANDARD COMMERCIALLY AVAILABLE COMPONENTS
USE COMMON PARTS ACROSS PRODUCT LINES
DESIGN FOR EASE OF PART FABRICATION
DESIGN PARTS WITH TOLERANCE THAT ARE WITHIN PROCESS CAPABILITY
MINIMIZE USE OF FLEXIBLE COMPONENT
DESIGN FOR EASE OF ASSEMBLY
USE MODULAR DESIGN
REDUCE ADJUSTMENT REQUIRED

STEPS TO MINIMIZE THE NUMBER OF PARTS

USE OF INCORPORATE HINGS
USE OF INTEGRAL SPRINGS
USE OF SNAP FITS
USE OF GUIDES BEARINGS
USE OF COVERS

6 0

3 years ago

Derive the probability that a receptor is occupied by a ligand using a model that treats the L ligands in solution as distinguis

love history [14]

that is the same thing as you are not going through this week or something

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3 years ago

Water flows through a horizontal 60 mm diameter galvanized iron pipe at a rate of 0.02 m3/s. If the pressure drop is 135 kPa per

maksim [4K]

Answer:

pipe is old one with increased roughness

Explanation:

discharge is given as

$V =\frac{Q}{A} = \frac{ 0.02}{\pi \4 \times (60\times 10^{-3})^2}$

V = 7.07 m/s

from bernou;ii's theorem we have

$\frac{p_1}{\gamma} +\frac{V_1^2}{2g} + z_1 = \frac{p_2}{\gamma} +\frac{V_2^2}{2g} + z_2 + h_l$

as we know pipe is horizontal and with constant velocity so we have

$\frac{P_1}{\gamma } + \frac{P_2 {\gamma } + \frac{flv^2}{2gD}$

$P_1 -P_2 = \frac{flv^2}{2gD} \times \gamma$

$135 \times 10^3 = \frac{f \times 10\times 7.07^2}{2\times 9.81 \times 60 \times 10^{-5}} \times 1000 \times 9.81$

solving for friction factor f

f = 0.0324

fro galvanized iron pipe we have $\epsilon = 0.15 mm$

$\frac{\epsilon}{d} = \frac{0.15}{60} = 0.0025$

reynold number is

$Re =\frac{Vd}{\nu} = \frac{7.07 \times 60\times 10^{-3}}{1.12\times 10^{-6}}$

Re = 378750

from moody chart

$For Re = 378750 and \frac{\epsilon}{d} = 0.0025$

$f_{new} = 0.025$

therefore new friction factor is less than old friction factoer hence pipe is not new one

now for Re = 378750 and f = 0.0324

from moody chart

we have $\frac{\epsilon}{d} =0.006$

$\epsilon = 0.006 \times 60$

$\epsilon = 0.36 mm$

thus pipe is old one with increased roughness

5 0

3 years ago

The solid rod BC has a diameter of 30 mm and is made of an aluminum for which the allowable shearing stress is 25 MPa. Rod AB is

nexus9112 [7]

Answer:

The solid rod BC has a diameter of 30 mm and is made of an aluminum for which the allowable shearing stress is 25 MPa. Rod AB is hollow and has an outer diameter of 25 mm; it is made of a brass for which the allowable shearing stress is 50 MPa.

4 0

3 years ago

Why do union members generally earn higher wages than non-union workers?

mariarad [96]

Answer:

the 1st option

Explanation:

7 0

3 years ago

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