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monitta
3 years ago
13

The compression ratio of most small gasoline engines falls between_______and________.

Engineering
2 answers:
Radda [10]3 years ago
7 0

Answer:

I think it's the second option, because if you look it up anywhere, small gas engines use a compression ratio of 8:1, and the only option with 8:1 is the second option. So "the compression ratio of most small gasoline engines fall between 8:1 and 11:1."

vichka [17]3 years ago
4 0

Answer:

J

Explanation:

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There are now six major branches of engineering: Mechanical, Chemical, Civil, Electrical, Management, and Geotechnical, and literally hundreds of different subcategories of engineering under each branch.

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2 years ago
What are the horizontal structures beneath a slab that help transfer the load from the slab to the columns?
Delicious77 [7]

Answer: D) Beams

Explanation:

3 0
2 years ago
Read 2 more answers
Independent auto lots usually have ____ finance rates than dealerships
wel

Independent auto lots usually have <u>higher</u> finance rates than dealerships

<u>Explanation:</u>

The finance rates that are charged by the dealers are lower than the finance charges that are charged by the independent auto. In case if you are getting financed through dealerships, you can also negotiate with them to charge finance rates and lower the charges of the finance.

But this negotiation and lowering of the finance rates is not possible with the independent auto lots and thus they charge higher rates compared to the dealerships.

8 0
3 years ago
A material point in equilibrium has 1 independent component of shear stress in the xz plane. a)True b)- False
ozzi

Answer:

True

Explanation:

For point in xz plane the stress tensor is given by\left[\begin{array}{ccc}Dx_{} &txz\\tzx&Dz\\\end{array}\right]

where Dx is the direct stress along x ; Dz is direct stress along z ;  tzx and txz are the  shear stress components

We know that the stress tensor matrix is symmetrical which means that tzx = txz  ( obtained by moment equlibrium )

thus we require only 1 independent component of shear stress to define the whole stress tensor at a point in 2D plane

8 0
2 years ago
A labor-intensive process to manufacture a product has a fixed cost of $338,000 and a variable cost of $143 per unit. An automat
ozzi

Answer:

no of unit is 17941

Explanation:

given data

fixed cost = $338,000

variable cost = $143 per unit

fixed cost = $1,244,000  

variable cost = $92.50 per unit

solution

we consider here no of unit is = n

so here total cost of labor will be sum of fix and variable cost i.e

total cost of labor = $33800 + $143 n  ..........1

and

total cost of capital intensive  = $1,244,000 + $92.5 n   ..........2

so here in both we prefer cost of capital if cost of capital intensive less than cost of labor

$1,244,000 + $92.5 n  <  $33800 + $143 n

solve we get

n > \frac{906000}{50.5}

n > 17941

and

cost of producing less than selling cost so here

$1,244,000 + $92.5 n < 197 n

solve it we get

n > \frac{1244000}{104.5}  

n > 11904

so in both we get greatest no is 17941

so no of unit is 17941

3 0
3 years ago
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