Answer:
a. 33120MJ
b. 5.6
c. 48
Explanation:
∆U= 120,000 KJ/h
Since
1 day = 24 hrs
14 days =24 x 14 hrs
14 days = 336 hrs
∆U = 120000 x 336 KJ
=40320000KJ
K = 1000
M = 1000000
∆U = 403200 MJ
Work done
W= 2000 KW.h ( 1 h = 3600 s)
W= 7200 MJ
According to the first law of thermodynamics
∆U = Q+W
Q= 40320 - 7200 MJ
1)Qa=33120 MJ
Coefficient of performance
COP = ∆U/W
COP= 40320 / 7200
2)COP = 5.6
3)COP of ideal heat pump
Th/(Th - Tl)
Th = 15°C
Tl = 9°C
Convert Celsius to Kelvin
273 + 15 = 288
288/(15-9)
288/6
48
COP= 48
Answer:
In refrigeration cycle heat transfer from inside refrigeration
In heat pump cycle heat transfer from environment
Explanation:
heat cycle is mechanical process use for cool the temperature but
In refrigeration heat transfer from inside of refrigeration that decrease temperature of refrigerator and in heat pump it decrease temperature negligible as compare to refrigerator
Answer:
Block design test. A block design test is a subtest on many IQ test batteries used as part of assessment of human intelligence. It is thought to tap spatial visualization ability and motor skill.
Explanation:
