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3 years ago

Which of the following does NOT describe product design.

Engineering

1 answer:

Andrew [12]3 years ago

6 0

Question:

Which of the following does NOT describe product design for maximum supply chain flexibility?

A. Create an increased number of modular products with fewer components.

B. Complete product assembly as close to receipt of actual orders as possible.

C. Reengineer products to use the same components.

D. Create many products variations.

Answer:

The correct option is;

D. Create many products variations

Explanation:

The options are analysed as follows

A. Create an increased number of modular products with fewer components.

Modularity increases the utilization of components such that manufacturers can create a wide variety of possible products that increases costumer satisfaction while maintaining utilization convenience

B. Complete product assembly as close to receipt of actual orders as possible.

Here we have requirement for improved supply chain flexibility as such improving raw material utilization rate and overall manufacturing efficiency

C. Reengineer products to use the same components.

Here we have increasing modularization which improves design flexibility and manufacturing comparative advantage

D. Create many products variations.

The above creates many varying components which increases the number of components to be assembled into products hence it does not describe product design for maximum supply chain flexibility.

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3 years ago

If the specific surface energy for aluminum oxide is 0.90 J/m2 and its modulus of elasticity is (393 GPa), compute the critical

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Answer:

critical stress required for the propagation is 27.396615 × $10^{6}$ N/m²

Explanation:

given data

specific surface energy = 0.90 J/m²

modulus of elasticity E = 393 GPa = 393 × $10^{9}$ N/m²

internal crack length = 0.6 mm

to find out

critical stress required for the propagation

solution

we will apply here critical stress formula for propagation of internal crack

( σc ) = $\sqrt{\frac{2E\gamma s}{\pi a}}$ .....................1

here E is modulus of elasticity and γs is specific surface energy and a is half length of crack i.e 0.3 mm = 0.3 × $10^{-3}$ m

so now put value in equation 1 we get

( σc ) = $\sqrt{\frac{2E\gamma s}{\pi a}}$

( σc ) = $\sqrt{\frac{2*393*10^9*0.90}{\pi 0.3*10^{-3}}}$

( σc ) = 27.396615 × $10^{6}$ N/m²

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3 years ago

A plate of an alloy steel has a plane-strain fracture toughness of 50 MPa√m. If it is known that the largest surface crack is 0.

Ivahew [28]

Answer:

option B is correct. Fracture will definitely not occur

Explanation:

The formula for fracture toughness is given by;

K_ic = σY√πa

Where,

σ is the applied stress

Y is the dimensionless parameter

a is the crack length.

Let's make σ the subject

So,

σ = [K_ic/Y√πa]

Plugging in the relevant values;

σ = [50/(1.1√π*(0.5 x 10^(-3))]

σ = 1147 MPa

Thus, the material can withstand a stress of 1147 MPa

So, if tensile stress of 1000 MPa is applied, fracture will not occur because the material can withstand a higher stress of 1147 MPa before it fractures. So option B is correct.

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