Answer:
D'(-2, 5), E'(3, 5), F'(3, 3), G'(-2, 3)
Step-by-step explanation:
Adding (-1, 2) to each of the coordinates gives ...
D +(-1, 2) = (-1-1, 3+2) = D'(-2, 5)
E +(-1, 2) = (4-1, 3+2) = E'(3, 5)
F +(-1, 2) = (4-1, 1+2) = F'(3, 3)
G +(-1, 2) = (-1-1, 1+2) = G'(-2, 3)
The answer is B.
I got it correct on Edge 2020
Distance (rounded to the nearest hundredth): 2.23
Slope: -2
width = w
length = w +2
perimeter = 2L + 2w
40 = 2(w+2) + 2w
40 = 2w+4 +2w
40 = 4w+4
36=4w
w=36/4 = 9
with = 9
length = 9+2 = 11
area = l x w = 9*11 = 99 square cm
v
v is 5/-2 on the graph
........,......
Question: Given that BE bisects ∠CEA, which statements must be true? Select THREE options.
(See attachment below for the figure)
m∠CEA = 90°
m∠CEF = m∠CEA + m∠BEF
m∠CEB = 2(m∠CEA)
∠CEF is a straight angle.
∠AEF is a right angle.
∠AEF is a right angle
Line AE is perpendicular to line CF, which is a straight line. This creates two right angles, <CEA and <AEF.
Angle on a straight line = 180°. Therefore, m<CEA + m<AEF = m<CEF. Each right angle measures 90°.
Thus, the three statements that must be TRUE are:
First account (simple interest)
The amount of interest earned by the first account is ...
I = Prt = $2000·0.04·7 = $2000·0.28 = $560
The amount in the second account at the end of 7 year is ...
FV = P·(1+r)^t = $2000·1.02^7 = $2297.37
so you have earned $297.37 in interest on the second account.
$560 is more than $297, so the First Account (simple interest) earns more money.