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Bess [88]
3 years ago
7

A hydrometre with a uniform cross-sectional area floats in a liquid of density 0.80cm^-3.If the hydrometre wieighs 100.0g and ha

s 12.0cm of its length below the liquid surface , calculate the cross-sectional area of the hydrometre
Physics
1 answer:
irakobra [83]3 years ago
6 0

Answer:

Explanation:

Let the cross sectional area be a cm .

volume of hydrometer inside liquid = 12 x a = 12 a

weight of liquid displaced = 12a x .8 x g = 9.6 a g

For free floatation of liquid

weight of hydrometer = weight of displaced liquid

9.6 a g = 100 g

a = 10.41 cm²

cross sectional area = 10.41 cm².

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A spherical balloon is deflating at 10 cm3/s. At what rate is the radius changing when the volume is 1000π cm3 ? What is the rat
just olya [345]

Answer:

1.dr/dt=0.0096cm/s

2. dA/dt=2.19cm^2/s

Explanation:

A spherical balloon is deflating at 10 cm3/s. At what rate is the radius changing when the volume is 1000π cm3 ? What is the rate of change of surface area at this moment?

for this question, we need to analyze the parameters we know

V=volume of the spherical balloon 1000π cm3

volume of the sphere=\frac{4}{3} \pi r^{3}

1000π=4/3πr^3

dividing both sides by 4

250*3=r^3

r=9.08cm, the radius of the balloon

dv/dt=dv/dr*dr/dt...................................1

dv/dr  ,means

V=\frac{4}{3} \pi r^{3}

dv/dr=4*pi*r^2

dv/dt=10 cm3/s

from equ 1

10=4*pi*9.08^2*dr/dt

10=1036 dr/dt

dr/dt=10/1036

dr/dt=0.0096cm/s

2. to find the rate at which the area is changing we have,

dA/dt=dA/dr*dr/dt

area of a sphere is  4πr^2

differentiate a with respect to r, radius

dA/dr=8πr

dA/dt=8πr*0.0096

dA/dt=8*pi*9.08*0.0096

dA/dt=2.19cm^2/s

is the rate of change of the surface area

7 0
3 years ago
The carpenter question plz ASAP
k0ka [10]

Answer:

d. The hammer falls with a constant acceleration

Explanation:

Since gravity is the only thing that is acting on the hammer as it falls and gravity is a form of acceleration then acceleration of 9.81m/s² which is gravity is the correct answer.

6 0
3 years ago
What is meant by specific latent heat of fussion​
Lunna [17]

Answer:

Boiling point of water is 100 deg C. It takes about 540 cal to change 1 g of water at the boiling point to 1 g of steam at 100 deg C.

5 0
2 years ago
A solid metal ball of radius 1.5 cm bearing a charge of -15 nC is located near a hollow plastic ball of radius 1.9 cm bearing a
blsea [12.9K]

We have that the electric field at the center of the metal ball due only to the charges on the surface of the metal ball is

E=7*10^{9}N/C

From the question we are told that

A solid metal ball of radius 1.5 cm

bearing a charge of -15 nC is located near a hollow plastic ball of radius 1.9 cm bearing

uniformly distributed charge of -7 nC

The distance between the centers of the balls is 9 cm

Generally the equation for the electric field  is mathematically given as

E=\frac{kq_2}{d^2}\\\\E=\frac{(9*10^9)7*10^{-2}}{9*10^{-2}}\\\\

E=7*10^{9}N/C

For more information on this visit

brainly.com/question/21811998

4 0
3 years ago
Một người đi xe đạp trong 40 phút với vận tốc là 12km/h. Hỏi quãng đường đi được là bao nhiêu?
Karo-lina-s [1.5K]

Answer:

khoảng cách = 8km / h

Explanation:

khoảng cách = tốc độ / thời gian

khoảng cách = 12/40

khoảng cách = 8km / h

3 0
2 years ago
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