The answer is: by using evidence from many investigations
Answer:
False
Explanation:
Pascal is a pressure of one newton per square metre, or, in SI base units, one kilogram per metre per second squared.
Pa = N/m^2
Answer:
![c=10\ J/kg^{\circ} C](https://tex.z-dn.net/?f=c%3D10%5C%20J%2Fkg%5E%7B%5Ccirc%7D%20C)
Explanation:
Given that,
Heat required, Q = 1200 J
Mass of the object, m = 20 kg
The increase in temperature, ![\Delta T=6^{\circ} C](https://tex.z-dn.net/?f=%5CDelta%20T%3D6%5E%7B%5Ccirc%7D%20C)
We need to find the specific heat of the object. The heat required to raise the temperature is given by :
![Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{1200}{20\times 6}\\\\c=10\ J/kg^{\circ} C](https://tex.z-dn.net/?f=Q%3Dmc%5CDelta%20T%5C%5C%5C%5Cc%3D%5Cdfrac%7BQ%7D%7Bm%5CDelta%20T%7D%5C%5C%5C%5Cc%3D%5Cdfrac%7B1200%7D%7B20%5Ctimes%206%7D%5C%5C%5C%5Cc%3D10%5C%20J%2Fkg%5E%7B%5Ccirc%7D%20C)
So, the specific heat of the object is
.
Answer:
Maximum contact force = 487.4 N
Explanation:
The graph showing force vs time is attached to the solution of this question.
According to the an interpretation of Newton's second law of motion, the magmitude of the change in momentum is equal to the magnitude of the impulse experienced duting this impact.
F.t = Δ(momemtum)
Δ(momemtum) = 0.044 [36 - (-36)] = 0.044 × 72 = 3.168 kgm/s
Meaning, Impulse = 3.168 kgm/s too.
The area under the curve above is the impulse we just obtained.
If the maximum contact force is called F
The impulse = Area under this graph
= (1/2)(F)(4-0) + (F)(7-4) + (1/2)(F)(10-7)
= 2F + 3F + 1.5F = (6.5F) mN.s = (0.0065F) N.s
0.0065F = 3.168
F = (3.168/0.0065) = 487.4 N
Hope this Helps!!!
If both waves have the same wavelength, then the amplitude of
their sum could be anything between 1 cm and 9 cm, depending
on the phase angle between them.
If the waves have different wavelengths, then the resultant is a beat
with an amplitude of 9 cm.