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iogann1982 [59]
2 years ago
8

If you push a 200 kg box with a horizontal force of 1,172 N and kinetic friction resists the motion with a force of 962 N, what

is the resultant acceleration in m/s2
Physics
1 answer:
Lynna [10]2 years ago
5 0

Answer:

a = 1.05m.s²

Explanation:

Fnet = m×a

Fapplied - friction = m×a

1172 - 962 = 200 × a

210 = 200a

a = 1.05

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nikklg [1K]

Answer:

1600 \frac{m}{s^2}

Explanation:

Acceleration is defined as the change in velocity divided by the time it took to produce such change. The formula then reads:

a = \frac{change-in-velocity}{time} = \frac{Vf-Vi}{t}

Where Vf is the final velocity of the object, (in our case 80 m/s)

Vi is the initial velocity of the object (in our case 0 m/s because the object was at rest)

and t is the time it took to change from the Vi to the Vf (in our case 0.05 seconds.

Therefore we have:

a = \frac{80 m/s - 0 m/s}{0.05 sec} = 1600 \frac{m}{s^2}

Notice that the units of acceleration in the SI system are \frac{m}{s^2} (meters divided square seconds)

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3 years ago
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PtichkaEL [24]

It's true, when we lift an object we add energy to it.

because, when we lift an object by applying force , the object attains a height and hence the energy gets stored in it, in the form gravitational potential energy .

6 0
3 years ago
Please help! thank you​
BlackZzzverrR [31]

Answer:

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Which type of force describes the force applied to an object?
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A visible light has a wavelength of 727.3 nm. Determine its frequency, energy per photon, and color.
Snezhnost [94]

Answer:

f=4.12\times 10^{14}\ Hz and E=2.73\times 10^{-19}\ J

Explanation:

The wavelength of a visible light is 727.3 nm.

727.3\ nm=727.3 \times 10^{-9}\ m

The formula is as follows :

c=f\lambda

f is the frequency of the visible light

f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{727.3 \times 10^{-9}}\\\\f=4.12\times 10^{14}\ Hz

Energy of a photon is given by :

E = hf, h is Planck's constant

E=6.63\times 10^{-34}\times 4.12\times 10^{14}\\\\E=2.73\times 10^{-19}\ J

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3 years ago
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