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iogann1982 [59]

1 year ago

8

If you push a 200 kg box with a horizontal force of 1,172 N and kinetic friction resists the motion with a force of 962 N, what

is the resultant acceleration in m/s2

1 answer:

Lynna [10]1 year ago

5 0

Answer:

a = 1.05m.s²

Explanation:

Fnet = m×a

Fapplied - friction = m×a

1172 - 962 = 200 × a

210 = 200a

a = 1.05

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