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3 years ago

Sodium undergoes beta decay and becomes magnesium, write an equation. please help...

Physics

1 answer:

Tatiana [17]3 years ago

6 0

Remark

There are 2 kinds of Beta Decay. This one is an example of a neutron becomes a proton and the emitted particle is an electron.

$_{11}^{23}\text{Na}\longrightarrow_{12}^{23}\text{Mg}+_{-1}^{ 0}\text{1e-}$

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A 3.6kg mass is accelerated at 2.5m/s. Calculate the resultant force<br> acting on it.

AleksandrR [38]

Force = mass*acceleration so
3.6*2.5 =9 Newtons

5 0

2 years ago

Consider an electron with charge −e and mass m orbiting in a circle around a hydrogen nucleus (a single proton) with charge +e.

alexandr1967 [171]

Answer:

$v=\sqrt{k\frac{e^2}{m_e r}}$ , $2.18\cdot 10^6 m/s$

Explanation:

The magnitude of the electromagnetic force between the electron and the proton in the nucleus is equal to the centripetal force:

$k\frac{(e)(e)}{r^2}=m_e \frac{v^2}{r}$

where

k is the Coulomb constant

e is the magnitude of the charge of the electron

e is the magnitude of the charge of the proton in the nucleus

r is the distance between the electron and the nucleus

v is the speed of the electron

$m_e$ is the mass of the electron

Solving for v, we find

$v=\sqrt{k\frac{e^2}{m_e r}}$

Inside an atom of hydrogen, the distance between the electron and the nucleus is approximately

$r=5.3\cdot 10^{-11}m$

while the electron mass is

$m_e = 9.11\cdot 10^{-31}kg$

and the charge is

$e=1.6\cdot 10^{-19} C$

Substituting into the formula, we find

$v=\sqrt{(9\cdot 10^9 m/s) \frac{(1.6\cdot 10^{-19} C)^2}{(9.11\cdot 10^{-31} kg)(5.3\cdot 10^{-11} m)}}=2.18\cdot 10^6 m/s$

7 0

3 years ago

Consider a sound wave moving through the air modeled with the equation s(x, t) = 5.00 nm cos(60.00 m−1x − 18.00 ✕ 103 s−1t). Wha

GaryK [48]

Answer:

Shortest time = 58.18 × 10^(-6) s

Explanation:

We are given;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t))

Let us set x = 0 as origin.

Now, for us to find the time difference, we need to solve 2 equations which are;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t1))

And

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t2))

Now, since the wave starts from maxima at time at t = 0, the required time would be the difference (t2 - t1)

Thus, the solutions are;

t1 = (1/(18 × 10³)) cos^(-1) (2.5/5)

And

t2 = (1/(18 × 10³)) cos^(-1) (-2.5/5)

Angle of the cos function is in radians, thus;

t1 = 58.18 × 10^(-6) s

t2 = 116.36 × 10^(-6) s

So,

Required time = t2 - t1 = (116.36 × 10^(-6) s) - (58.18 × 10^(-6) s) = 58.18 × 10^(-6) s

4 0

3 years ago

If a electrician measures the current of a circuit to be 100 Amps and the circuit is only designed to have a current of 80 Amps,

Talja [164]

There are too many batteries in the circuit, which increased the emf of the circuit and in turn increased the current in the circuit.

<h3>Current in the circuit</h3>

The current in the circuit is determined by applying Ohms law as shown below;

V = IR

where;

I is the current
V is the voltage
R is the resistance

I = V/R

At a constant resistance of the circuit, the current in a circuit will increase when the emf of the circuit increases.

Thus, we can conclude that, there are too many batteries in the circuit, which increased the emf of the circuit and in turn increased the current in the circuit.

Learn more about current in circuit here: brainly.com/question/13195529

6 0

2 years ago

Technician A says that if starter drive clearance is too small, the starter will produce a noise during cranking. Technician B s

Ronch [10]

Answer:

Both Technicians A and B are wrong in there answers.

Explanation:

Starter Drives are rotating mechanical component use to drive another component (flywheel) to start an engine. And thus they are known as starters. Starters are smaller than the component they drive. They are found commonly in automobiles.

The starter and the driven component(gear) are supposed to fit closely, with some clearance between the two gears so as to operate without noise. When the<u> clearance is too small </u>there will be a <u>noise after cranking,</u> and when the <u>clearance is too great</u> there be <u>noise before cranking</u>.

Cranking simply means starting an engine or the initial rotating of an engine to start it.

8 0

3 years ago