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Arisa [49]
3 years ago
12

Sodium undergoes beta decay and becomes magnesium, write an equation. please help...

Physics
1 answer:
Tatiana [17]3 years ago
6 0

Remark

There are 2 kinds of Beta Decay. This one is an example of a neutron becomes a proton and the emitted  particle is an electron.

_{11}^{23}\text{Na}\longrightarrow_{12}^{23}\text{Mg}+_{-1}^{ 0}\text{1e-}



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The equation formula:
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An experimental 1500-kg car travels at a constant speed of 22 m/s around a circular test track that is 80 m across. What is the
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363000 J or 363 kJ

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Two vertical springs have identical spring constants, but one has a ball of mass m hanging from it and the other has a ball of m
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To solve this problem we will start from the definition of energy of a spring mass system based on the simple harmonic movement. Using the relationship of equality and balance between both systems we will find the relationship of the amplitudes in terms of angular velocities. Using the equivalent expressions of angular velocity we will find the final ratio. This is,

The energy of the system having mass m is,

E_m = \frac{1}{2} m\omega_1^2A_1^2

The energy of the system having mass 2m is,

E_{2m} = \frac{1}{2} (2m)\omega_1^2A_1^2

For the two expressions mentioned above remember that the variables mean

m = mass

\omega =Angular velocity

A = Amplitude

The energies of the two system are same then,

E_m = E_{2m}

\frac{1}{2} m\omega_1^2A_1^2=\frac{1}{2} (2m)\omega_1^2A_1^2

\frac{A_1^2}{A_2^2} = \frac{2\omega_2^2}{\omega_1^2}

Remember that

k = m\omega^2 \rightarrow \omega^2 = k/m

Replacing this value we have then

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Therefore the ratio of the oscillation amplitudes it is the same.

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