Complete Question
An electron is accelerated by a 5.9 kV potential difference. das (sd38882) – Homework #9 – yu – (44120) 3 The charge on an electron is 1.60218 × 10−19 C and its mass is 9.10939 × 10−31 kg. How strong a magnetic field must be experienced by the electron if its path is a circle of radius 5.4 cm?
Answer:
The magnetic field strength is 
Explanation:
The work done by the potential difference on the electron is related to the kinetic energy of the electron by this mathematical expression

Making v the subject
Where m is the mass of electron
v is the velocity of electron
q charge on electron
is the potential difference
Substituting values
f

For the electron to move in a circular path the magnetic force[
] must be equal to the centripetal force[
] and this is mathematically represented as

making B the subject

r is the radius with a value = 5.4cm = 
Substituting values


It is important to have the international system of units 'cause <span>it can be used by scientists everywhere around the world, and they will be able to understand each other with more accuracy.
In short, Your Answer would be Option D
Hope this helps!</span>
Answer:
Explanation:
There is reflection ( two times ) from upper and lower surface of the film . In both cases , reflection is from low to high density medium so there is change in phase of 180 twice .
So for constructive interference
2μd = n λ₁ , d is thickness required , λ is wavelength n₁ is order of bright fringe
For destructive interference ( minimum light )
2μd = (2n+1) λ₂/2
n λ₁ =(2n+1) λ₂/2
(2n+1) / 2n = λ₁ / λ₂
= 650 / 505
= 5 / 4 ( approx )
2n = 4
n = 2
2μd = n λ₁
2 x 1.33 x d = 2 x 650 nm
d = 488.72 nm