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-BARSIC- [3]
3 years ago
9

In an energy pyramid, the total energy available for consumption from one trophic level to the next one it is

Physics
1 answer:
Flura [38]3 years ago
5 0

Answer: Conserved

Explanation:

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The critical angle between a medium and air is 430. What is the speed of light in that medium?
vagabundo [1.1K]

Answer:

The speed of light is that medium is 281907786.2 m/s.

Explanation:

since the critical angle is Фc = 430, we know that the refractive index is given by:

n = 1/sin(Фc)

  = 1/sin(430)

  = 1.06

then if n is the refractive index of the medium and c is the speed of light, then the speed of light in the medium is given by:

v = c/n

  = (3×10^8)/(1.06)

  = 281907786.2 m/s

Therefore, the speed of light is that medium is 281907786.2 m/s.

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The main energy source during exercise of low to moderate intensity is
zhannawk [14.2K]

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THUS,THE MAJOR SOURCES OF ENERGY DURING EXERCISE ARE CARBOHYDRATES AND FATS.

Explanation:

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3 years ago
A young woman walks up 55 steps to the top of a water slide. She slides
navik [9.2K]

Answer:

potential energy PE = M g h

KE at bottom = 1/2 M V^2

Regardless of the slope of the slide the change in energy is the same

1/2 V^2 = g h

V = (2 g h)^1/2 = (2 * 9.8 m/s^2 * 10 m)^1/2 = 14 m / s

Perhaps the question says that h = 55 * .1 = 5.5 m

Then V = (2 * 9.8 * 5.5) = 10.4 m/s

5 0
2 years ago
A 2.02 nF capacitor with an initial charge of 4.55 µC is discharged through a 1.22 kΩ resistor. (a) Calculate the current in the
Mandarinka [93]

Answer:

a) 0.048A

b) 0.18µC

c) 1.85A

Explanation:

The discharged current of the capacitor as a function of time is given by:

i=\frac{q_o}{RC}*e^{-\frac{t}{\tau}}\\where:\\\tau=RC\\

\tau=1.22*10^3*2.02*10^{-9}\\\tau=2.46*10^{-6}s

a)

i=\frac{4.55\µC}{2.46\µs}*e^{-\frac{9\µs}{2.46\µs}}\\\\i=0.048A

b)

q=q_o*e^{-\frac{t}{\tau}}

q=4.55\µC*e^{-\frac{8\µs}{2.46\µs}}\\q=0.18\µC

c) the maximum current occurs when t=0

i=\frac{4.55\µC}{2.46\µs}*e^{-\frac{0\µs}{2.46\µs}}\\\\i=1.85A

6 0
3 years ago
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