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Artyom0805 [142]

3 years ago

12

How to do this problem

2 answers:

marusya05 [52]3 years ago

4 0

The answer I'm pretty sure is 3

STALIN [3.7K]3 years ago

3 0

You know the insect's mass.
You know the insect's acceleration.
==> Find the force on the insect. (F=Ma)

==> The force on the car is equal and opposite.

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How are physical traits inherited from one generation to the next?

Umnica [9.8K]

Http://www.nature.com/scitable/topicpage/inheritance-of-traits-by-offspring-follows-predictable-6524... this should answer all questions you have on this specific subject in science

3 0

4 years ago

A boy of mass 30.0 kg is sledding down a 70.0-m slope starting from rest. The slope is angled at 15.0° below the horizontal. Aft

Studentka2010 [4]

The speed of the boy and his friend at the bottom of the slope is 16.52 m/s.

<h3>Their speed at the bottom</h3>

Apply the principle of conservation of energy,

E(up) - E(friction) = E(bottom)

mg sin(15) + ¹/₂(M + m)u² - μ(M + m)cos 15 = ¹/₂(M + m)v²

$v = \sqrt{2[\frac{mgd \ sin15 \ + \frac{1}{2}(M + m)u^2 \ -\mu (M + m)g cos\ 15 }{M + m}] }$

where;

u is the speed of the after 28 m

u = √2gh

u = √(2gL sin15)

u = √(2 x 9.8 x 28 x sin 15)

u = 11.92 m/s

$v = \sqrt{2[\frac{(30)(9.8)(70) \ sin15 \ + \frac{1}{2}(30 + 50)(11.92)^2 \ - 0.12 (30 + 50)9.8 cos\ 15 }{30 + 50}] }\\\\v = 16.52 \ m/s$

Thus, the speed of the boy and his friend at the bottom of the slope is 16.52 m/s.

Learn more about speed here: brainly.com/question/6504879

#SPJ1

8 0

2 years ago

If the earth were twice the distance from the sun that it is now, the gravitational force exerted on it by the sun would be: a)

devlian [24]

Answer:

a) 1/4 what it is now

Explanation:

As we know that force of gravitation between two planets at some distance "r" from each other is given as

$F_g = \frac{Gm_1m_2}{r^2}$

now since we know that if the distance between Earth and Sun is changed

So the force of gravity will be given as

$\frac{F_g'}{F_g} = \frac{r_1^2}{r_2^2}$

now we know that the distance between sun and earth is changed to twice the initial distance between them

so we have

$r_2 = 2r_1$

so new gravitational force between sun and earth is given as

$F_g' = \frac{r_1^2}{(2r_1)^2}F_g$

$F_g' = \frac{1}{4}F_g$

4 0

3 years ago

After the switch in is closed on point a, there is current i through resistance r. gives the current for four sets of values of

vovangra [49]

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8 0

3 years ago

Which of newtons laws accounts for the following statement " Negative acceleration is proportional to applied braking force "

fenix001 [56]

I believe that would be his second law!

4 0

4 years ago