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Artyom0805 [142]
3 years ago
12

How to do this problem

Physics
2 answers:
marusya05 [52]3 years ago
4 0
The answer I'm pretty sure is 3
STALIN [3.7K]3 years ago
3 0
You know the insect's mass.
You know the insect's acceleration.
==> Find the force on the insect. (F=Ma)

==> The force on the car is equal and opposite.
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A system absorbed 44 joules of heat from its surroundings. After doing work, the increase in the internal energy of the system i
Lelu [443]
We can solve the problem by using the first law of thermodynamics:
\Delta U = Q-W
where
\Delta U is the variation of internal energy of the system
Q is the heat absorbed by the system
W is the work done by the system

In this problem, the heat absorbed by the system is Q=+44 J, and the increase in internal energy is \Delta U = +32 J. So we can rearrange the equation to calculate the work done:
W=Q-\Delta U=44 J-32 J=+12 J
and the work is positive, which means that it is done by the system on the surrounding.
4 0
3 years ago
Read 2 more answers
What is the person called when they deliver babies from the womb?
Verizon [17]
This is an obstetrician. Also called for short OB/GYN. They are doctors that specialize in delivering babies and the female reproductive system.
8 0
3 years ago
Which example shows an endothermic reaction?
Nata [24]

Answer:

reactants --> products + thermal energy

Explanation:

Heat is absorbed in endothermic reaction.

6 0
2 years ago
A 10n force is applied to a 25kg mass to slide it across a frictional surface. What is the acceleration of the mass?
klasskru [66]

Answer: a = 0.4m/s^2 - 9.8*c where c is the coefficient of kinetic friction of the surface

Explanation: We know that, by the second Newton's law, a = F/m

where a is the acceleration, F is the net force and m is the mass of the object.

Then, if the surface is frictionless, the total force applied in the object is 10N, and the mass of the object is 25kg, so the acceleration is:

a =10N/25kg = 0.4m/s^2.

But if the surface is frictional, there will be a force of friction applied in the mass (this depends on the coefficient of friction and the weight of the mass), this means that the acceleration will be reduced.

If = -(9.8*25)*c

where c is a number that is bigger than 0 and smaller than 1, is called the coefficient of kinetic friction.

So the total force is now:

F = (10 - 9.8*25*c)

Then, the acceleration in a frictional surface is equal to:

a = (10 - 9.8*25*c)/25 = 0.4m/s^2 - 9.8*c

6 0
3 years ago
Read 2 more answers
A 460 g , 6.0-cm-diameter can is filled with uniform, dense food. It rolls across the floor at 1.1 m/s . Part A What is the can'
Reika [66]

Answer:

the can's kinetic energy is 0.42 J

Explanation:

given information:

Mass, m = 460 g = 0.46 kg

diameter, d = 6 cm, so r = d/2 = 6/2 = 3 cm = 0.03 m

velocity, v = 1.1 m/s

the kinetic energy of the can is the total of kinetic energy of the translation and rotational.

KE = \frac{1}{2} I ω^2 + \frac{1}{2} mv^{2}

where

I = \frac{1}{2} mr^{2} and ω = \frac{v}{r}

thus,

KE = \frac{1}{2} \frac{1}{2} mr^{2} (\frac{v}{r})^2 + \frac{1}{2} mv^{2}

     = \frac{1}{2} \frac{1}{2} mr^{2} \frac{v^{2} }{r^{2}} + \frac{1}{2} mv^{2}

     = \frac{1}{4} mv^{2} + \frac{1}{2} mv^{2}

     = \frac{3}{4} mv^{2}

     = \frac{3}{4} (0.46) (1.1)^{2}

     = 0.42 J

8 0
3 years ago
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