Answer:
Explanation:
Given that,
Mass of block
M = 2kg
Spring constant k = 300N/m
Velocity v = 12m/s
At t = 0, the spring is neither stretched nor compressed. Then, it amplitude is zero at t=0
xo = 0
It velocity is 12m/s at t=0
Then, it initial velocity is
Vo = 12m/s
Then, amplitude is given as
A = √[xo + (Vo²/ω²)]
Where
xo is the initial amplitude =0
Vo is the initial velocity =12m/s
ω is the angular frequency and it can be determine using
ω = √(k/m)
Where
k is spring constant = 300N/m
m is the mass of object = 2kg
Then,
ω = √300/2 = √150
ω = 12.25 rad/s²
Then,
A = √[xo + (Vo²/ω²)]
A = √[0 + (12²/12.5²)]
A = √[0 + 0.96]
A = √0.96
A = 0.98m
it is transfred through the basics
Answer:
The new speed of the ball is 176.43 m/s
Explanation:
Given;
mass of the ball, m = 7 kg
initial speed of the ball, u = 5 m/s
applied force, F = 300 N
time of force action on the ball, t = 4 s
Apply Newton's second law of motion;
where;
v is new speed of the ball
Therefore, the new speed of the ball is 176.43 m/s
Answer:
A. 51.42 m.
B. 17.14 s.
Explanation:
Using equations of motion:
vf^2 = vi^2 + 2 * aS
Where,
vf = final velocity
a = acceleration
S = distance to which swan traveled
vi = 0 m/s
6.00^2 = 2 * 0.350S
S = 36/0.7
= 51.42 m.
B.
vf = vi + at
6 = 0 + 0.35t
t = 6/0.35
= 17.14 s.
Speed = (distance covered) / (time to cover the distance).
= (1.92 meters) / (4.47 x 10⁻⁸ second)
= 42,950,000 meters/second (rounded to the nearest 10,000 m/s)
That's about 96.1 million miles per hour, or about 14% of the speed of light.
