- initial velocity=u=24m/s
- Acceleration=a=4m/s^2
- Distance=s=96m
- Final velocity=v
Using 3rd equation of kinematics







You need to set their position functions equal to one another and so for the time t when that is true. That is when the tiger and the deer are in the same place meaning the tiger catches the dear
Xdear= 2t+15 deer position function.
(I integrated the velocity function )
To get the Tigers position function you must integrate the acceleration twice. This becomes
Xtiger=t^2
Now t^2=2t+15
Time t is when the tiger catches the deer
t^2-2t-15=0
(t-5)(t+3)=0 factored
t=5s is the answer you use (t=-3 is a meaningless solution)
Answer:
Force plane exert on pilot = 4270 N
Explanation:
first convert radius and speed to ms
using formula from force we know that
mass = weight/ gravity = 700 N/ 9.8N/kg= 71.4 kg
Fc= N-mg
N= Fc+ mg As Fc = mv²/R
N= mv²/R + mg
taking m common
N= m( v²/R +g)
= 71.4( (200)²/ 800 + 9.8 )
Force = 4270 N
No mechanical waves cannot travel in a vacuum