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Ira Lisetskai [31]
3 years ago
11

An ultrasound machine is being used to try to identify potential kidney stones. The machine is working properly and no kidney st

ones are found. Which statement best describes this situation? The generated sound wave will not be able to reflect off of the object. The sound wave will not be generated, so there will be no echoes received. The echoes will be made but will not be able to be received by the machine. The machine will not be able to process the received echoes into images.
Physics
2 answers:
Kazeer [188]3 years ago
7 0

Answer:

The generated sound wave will not be able to reflect off of the object.

Explanation:

bonufazy [111]3 years ago
4 0

Answer:

Explanation:

e d g e n u i t y 2020

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Eric threw a baseball 20 meters in 0.5 seconds. What was the average speed of the baseball to the nearest hundredths of a m/sec.
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40m/sec

Explanation:

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speed = 20 ÷ 0.5

speed = 40 m/sec

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The human ear canal is, on average, 2.5cm long and aids in hearing by acting like a resonant cavity that is closed on one end an
Troyanec [42]

Answer:

3400 Hz

Explanation:

We know that

1 cm = 0.01 m

L = Length of the human ear canal = 2.5 cm = 0.025 m

V = Speed of sound = 340 ms⁻¹

f = First resonant frequency

The human ear canal behaves as a closed pipe and for a closed pipe, nth resonant frequency is given as

f = \frac{(2n - 1)V}{4L}

for first resonant frequency, we have n = 1

Inserting the values

f = \frac{(2(1) - 1) 340}{4(0.025)}

f = \frac{340}{4(0.025)}

f = 3400 Hz

4 0
3 years ago
A block on a horizontal frictionless plane is attached to a spring, as shown below. The block oscillates along the x-axis with s
AleksandrR [38]

The question is about unclear since no picture provided. But from the question, it could be guessed that the box is moving back and forth on the frictionless plane at the amplitude of A in simple harmonic motion.

Answer:

D. At x=0, it's acceleration is at a maximum

Explanation:

As the box move forward, it reaches point A and than move backward. Theoretically, the box will move backwards, through its origin, to point -A and then going forward.

Point A is the maximum displacement of the box in this case. At this point, the box instantaneously stop to go backward. Therefore the velocity at that moment is zero.

From point -A, the box travel forward and keep building up speed due to the release in potential energy of the spring. And at point x=0, the velocity become maximum. After point x=0, the velocity of the box slows down due to the conversion of kinetic energy to potential energy of the spring. And as it reaches point A, it reaches zero velocity.

The same can be said as the box travels backward from point A to -A

8 0
3 years ago
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