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Ira Lisetskai [31]
3 years ago
11

An ultrasound machine is being used to try to identify potential kidney stones. The machine is working properly and no kidney st

ones are found. Which statement best describes this situation? The generated sound wave will not be able to reflect off of the object. The sound wave will not be generated, so there will be no echoes received. The echoes will be made but will not be able to be received by the machine. The machine will not be able to process the received echoes into images.
Physics
2 answers:
Kazeer [188]3 years ago
7 0

Answer:

The generated sound wave will not be able to reflect off of the object.

Explanation:

bonufazy [111]3 years ago
4 0

Answer:

Explanation:

e d g e n u i t y 2020

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A 1kg dictionary is resting on a table that is 1.5m high. How much potential energy
melamori03 [73]

Answer:

Potential energy = 14.7 Joules.

Explanation:

Given the following data;

Mass, m = 1kg

Height, h = 1.5m

We know that acceleration due to gravity is equal to 9.8m/s²

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

P.E = mgh

Where, P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

P.E = mgh

Substituting into the equation, we have;

P.E = 1*9.8*1.5

P.E = 14.7 Joules.

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A karate master strikes a board with an initial velocity of 10.0 m/s, decreasing to 1.0 m/s as his hand passes through the board
kenny6666 [7]

The force exerted on the board by the karate master given the data is -4500 N

<h3>Data obtained from the question </h3>
  • Initial velocity (u) = 10 m/s
  • Final velocity (v) = 1 m/s
  • Time (t) = 0.002 s
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The force exerted can be obtained as illustrated below:

F = m(v - u) / t

F = 1 (1 - 10) / 0.002

F = (1 × -9) / 0.002

F = -4500 N

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b

Explanation:

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Answer:

The law of refraction states that the incident ray, the refracted ray, and the normal to the interface, all lie in the same plane.

Explanation:

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