Question

What is the 30th term of the linear sequence below? -4, -1,2,5,8,...

Answer 1

Answer:

The 30th term is 83

Step-by-step explanation:

we know that

An arithmetic sequence is a sequence of numbers such that the difference of any two successive members of the sequence is a constant called the common difference d

in this problem

$a_1=-4\\a_2=-1\\a_3=2\\a_4=5\\a_5=8$

so

$a_2-a_1=-1-(-4)=3\\a_3-a_2=-2-(-1)=3\\a_4-a_3=-5-2=3\\a_5-a_4=-8-5=3$

The common difference d is 3

We can write an Arithmetic Sequence as a rule:

$a_n=a_1+d(n-1)$

Find out the 30th term

we have

$n=30\\d=3\\a_1=-4$

substitute

$a_n=-4+(3)(30-1)$

$a_n=-4+(3)(29)$

$a_n=83$