Answer:
In this experiment, the period of the pendulum is the dependent variable. There are three independent variables: the pendulum mass, the amplitude of the swing, and the length of the pendulum string.
Explanation:
In the data, 0.20 ppm is an outlier and this can be rejected if there is a 95% confidence level.
<h3>What is an outlier?</h3>
When analyzing data an outlier is a value that is abnormal or too different from other data. In the case presented 0.20 can be tagged as an outlier because other values such as 0.11, 0.12, 0.13, and 0.14 are similar while 0.20 is outside this range.
<h3>Should this piece of data be rejected?</h3>
The general rule is that if there is a 95% of confidence or higher you can reject an outlier, knowing the other data occurs 95% of the time, and therefore the outlier is improbable.
Based on this, you can reject an outlier if the confidence level is 95%.
Learn more about outlier in: brainly.com/question/9933184
Answer:
(C) Mass of KCl(s), mass of H20, initial temperature of the water, and final temperature of the solution
Explanation:
molar enthalpy of solution of KCl(s) is heat evolved or absorbed when one mole of KCl is dissolved in water to make pure solution . The heat evolved or absorbed can be calculated by the following relation.
Q = msΔt where m is mass of solution or water , s is specific heat and Δt is change in temperature of water .
So data required is mass of water or solution , initial and final temperature of solution , specific heat of water is known .
Now to know molar heat , we require mass of solute or KCl dissolved to know heat heat absorbed or evolved by dissolution of one mole of solute .
Answer:
1. 6.116x1024 Molecules of H2O
2. 13400 L
3. 8.001x1024 Molecules of Mg3(PO4)2
4. 572 g.
5. 1.017x1025 Molecules of N2
6. 7.24 g
.7. 6980 g. of Al(OH)3
8. 3H2 + N2 => 2NH3
9. S8 + 8O2 => 8SO2
10. Ni(ClO3)2→ NiCl2 + 3O2
11. C2H4 + 3O2→ 2CO2 + 2H2O
12. 2KClO3→ 2KCl + 3O2
13. Cu(OH)2 + 2HC2H3O2→ Cu(C2H3O2)2 + 2H2O
14. C3H8 + 5O2→ 3CO2 + 4H2O
15. 191 g of CO
Answer:
3,200 joules
Explanation:
q = mcΔT = (250.0 g)(0.128 j/g°C)(100°C -25°C) = 3,200 joules
