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Karolina [17]
2 years ago
10

MOLE CONVERSIONS

Chemistry
1 answer:
madam [21]2 years ago
4 0

Answer:

1.    6.116x1024 Molecules of H2O

2.    13400 L

3.    8.001x1024 Molecules of Mg3(PO4)2

4.    572 g.

5.    1.017x1025 Molecules of N2

6.    7.24 g

.7.     6980 g. of Al(OH)3

8.    3H2 + N2    => 2NH3

9.    S8 + 8O2   => 8SO2

10.  Ni(ClO3)2→     NiCl2   +  3O2

11.  C2H4      +      3O2→      2CO2      +     2H2O

12.  2KClO3→      2KCl      +      3O2

13.  Cu(OH)2   +   2HC2H3O2→     Cu(C2H3O2)2      +     2H2O

14.  C3H8      +      5O2→      3CO2      +      4H2O

15.  191 g of CO

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Determine the number of milliliters of 0.00300 M phosphoric acid required to neutralize 40.00 mL of 0.00150 M calcium hydroxide.
a_sh-v [17]

The volume of H₃PO₄ : 13.33 ml

<h3>Further explanation</h3>

Given

0.003 M  Phosphoric acid-H₃PO₄

40 ml of 0.00150 M Calcium hydroxide-Ca(OH)₂

Required

Volume of H₃PO₄

Solution

Acid-base titration formula  

Ma. Va. na = Mb. Vb. nb  

Ma, Mb = acid base concentration  

Va, Vb = acid base volume  

na, nb = acid base valence  (amount of H⁺/OH⁻)

H₃PO₄⇒3H⁺ + PO₄³⁻ ⇒ 3 H⁺ = valence = 3

Ca(OH)₂⇒Ca²⁺ + 2OH⁻⇒ 2 OH⁻ = valence = 2

Input the value :

a = H₃PO₄, b = Ca(OH)₂

0.003 x Va x 3 = 0.0015 x 40 x 2

Va = 13.33 ml

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