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Vedmedyk [2.9K]
3 years ago
8

Determine if a bond between each pair of atoms would be pure covalent, polar covalent, or ionic.

Chemistry
1 answer:
Elden [556K]3 years ago
7 0
Types of Bonds can be predicted by calculating the difference in electronegativity.
If, Electronegativity difference is,

                Less than 0.4 then it is Non Polar Covalent
                
                Between 0.4 and 1.7 then it is Polar Covalent 
            
                Greater than 1.7 then it is Ionic

For C and N,
                    E.N of Nitrogen      =   3.04
                    E.N of Carbon        =   2.55
                                                   ________
                    E.N Difference             0.49          (Weakly Polar Covalent)

For N and S,
                    E.N of Nitrogen      =   3.04
                    E.N of Sulfur          =   2.58
                                                   ________
                    E.N Difference             0.46           (Weakly Polar Covalent)

For K and F,
                    E.N of Fluorine       =   3.98
                    E.N of Potassium   =   0.28
                                                   ________
                    E.N Difference             3.70          (Ionic)

For N and N,
                    E.N of Nitrogen      =   3.04
                    E.N of Nitrogen      =   3.04
                                                   ________
                    E.N Difference             0              (Non Polar Covalent)
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Explanation:

Since, it is shown that the reaction has been reversed. Therefore, value of K_{c} will become \frac{1}{K_{c}}.

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Also, the number of moles of each reactant has been halved. So, K_{c''} for the reaction MgO(s) + \frac{1}{2}Cl2(g) → MgCl_{2}(s) + \frac{1}{2} O2(g) will also get halved.

Therefore,     K_{c''}  = K_{c'} = (20)^{0.5}

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