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nikitadnepr [17]

3 years ago

15

Determine the correct set-up below to determine what mass, in grams, of N2 is needed to completely react with 105 g F2 ?

1 answer:

neonofarm [45]3 years ago

4 0

Answer:

C: 1 mol F2/38 g F2

Explanation:

The reaction equation is;

N2 + 3F2 = 2NF3

Now, to know how many grams, of N2 is needed to completely react with 105 g F2 and since the molar mass of N2 is 28.02 g/mol, Molar mass of F2 is 38 g/mol, number of moles attached to N2 and F2 in the reaction are 1 and 3 moles respectively, then we will have;

105 g F2 × 1 mol F2/38 g F2 × 1 mol N2/3 mol F2 × 28.02 g N2/1 mol N2

Option C is Thus correct

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How many milligrams of CO exist in 12000 liters of air with 10 ppm of CO?

VARVARA [1.3K]

Answer:

The mass of CO in 12,000 Liters of air is $12\times 10^4 mg$ .

Explanation:

The ppm is the amount of solute (in milligrams) present in one Liter of a solvent. It is also known as parts-per million.

To calculate the ppm of oxygen in sea water, we use the equation:

$\text{ppm}=\frac{\text{Mass of solute}(mg)}{\text{Volume of solution}(L)}$

The ppm concentration of CO = 10 ppm

Mass of CO = m

Volume of air = 12,000 L

$10 =\frac{m}{12,000 L}$

$m=10\times 12,000 mg=120,000 mg=12\times 10^4 mg$

The mass of CO in 12,000 Liters of air is $12\times 10^4 mg$ .

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If you are traveling at 60mi/hr, how many meters per second is that equivalent to?

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Answer:

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2 years ago

Convert 98.7 °F to Celsius<br> Formula for Fahrenheit to Celsius

dmitriy555 [2]

Answer:

$\boxed {\tt 37.0555556 \textdegree C}$

Explanation:

The formula to convert Fahrenheit to Celsius, use the following formula.

$C=(\textdegree F -32)*\frac{5}{9}$

We want to convert 98.7 degrees Fahrenheit to Celsius, so we must substitute 98.7 in for degrees Fahrenheit.

$C=(98.7 -32)*\frac{5}{9}$

Solve inside the parentheses. Subtract 32 from 98.7.

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Multiply 66.7 by 5/9.

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3 0

4 years ago

Read 2 more answers

Ozone (O 3) in the atmosphere can react with nitric oxide (NO): O 3(g) + NO(g) → NO 2(g) + O 2(g). Calculate the ΔG° for this re

Mandarinka [93]

Answer:

ΔG° = 1022. 8 kJ

Explanation:

ΔH° = –199 kJ/mol

ΔS° = –4.1 J/K·mol

T = 25°C = 25 + 273 = 298K (Converting to kelvin temperature)

ΔG° = ?

The relationship between these varriables are;

ΔG° = ΔH° - TΔS°

ΔG° = –199 - 298 (–4.1)

ΔG° = -199 + 1221.8

ΔG° = 1022. 8 kJ

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3 years ago

Which of these properties is most helpful when identifying a substance in a given sample of matter

dsp73

Answer:

melting point

Explanation:

its one of the physical properties of a substance

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