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nikitadnepr [17]
3 years ago
15

Determine the correct set-up below to determine what mass, in grams, of N2 is needed to completely react with 105 g F2 ?

Chemistry
1 answer:
neonofarm [45]3 years ago
4 0

Answer:

C: 1 mol F2/38 g F2

Explanation:

The reaction equation is;

N2 + 3F2 = 2NF3

Now, to know how many grams, of N2 is needed to completely react with 105 g F2 and since the molar mass of N2 is 28.02 g/mol, Molar mass of F2 is 38 g/mol, number of moles attached to N2 and F2 in the reaction are 1 and 3 moles respectively, then we will have;

105 g F2 × 1 mol F2/38 g F2 × 1 mol N2/3 mol F2 × 28.02 g N2/1 mol N2

Option C is Thus correct

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Answer:

Option A.

2Na + 2H2O —> 2NaOH + H2

Explanation:

To know which option is correct, we shall do a head count of the number of atoms present on both side to see which of them is balanced. This is illustrated below below:

For Option A:

2Na + 2H2O —> 2NaOH + H2

Reactant >>>>>>> Product

2 Na >>>>>>>>>>> 2 Na

4 H >>>>>>>>>>>> 4 H

2 O >>>>>>>>>>>> 2 O

Thus, the above equation is balanced.

For Option B:

2Na + 2H2O —> NaOH + H2

Reactant >>>>>>> Product

2 Na >>>>>>>>>>> 1 Na

4 H >>>>>>>>>>>> 3 H

2 O >>>>>>>>>>>> 1 O

Thus, the above equation is not balanced.

For Option C:

2Na + H2O —> 2NaOH + H2

Reactant >>>>>>> Product

2 Na >>>>>>>>>>> 2 Na

2 H >>>>>>>>>>>> 4 H

1 O >>>>>>>>>>>> 2 O

Thus, the above equation is not balanced.

For Option D:

Na + 2H2O —> NaOH + 2H2

Reactant >>>>>>> Product

1 Na >>>>>>>>>>> 1 Na

4 H >>>>>>>>>>>> 5 H

2 O >>>>>>>>>>>> 1 O

Thus, the above equation is not balanced.

From the illustrations made above, only option A is balanced.

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3 years ago
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Answer:

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Potassium permanganate, KMnO, and glycerin, C3H5(OH)3, react explosively according to the
Finger [1]

The volume of CO2 at STP =124.298 L

<h3>Further explanation</h3>

Given

Reaction

4 KMnO4, +4 C3H5(OH)5, -7K2CO3, + 7 Mn2O3, +5 CO2, + 16 H2O

701,52 g of KMnO4

Required

volume of CO2 at STP

Solution

mol KMnO4 (MW=158,034 g/mol) :

mol = mass : MW

mol = 701.52 : 158.034

mol = 4.439

mol CO2 from equation : 5/4 x mol KMnO4 = 5/4 x 4.439 = 5.549

At STP 1 mol = 22.4 L, so for 5.549 moles :

=5.549 x 22.4

=124.298 L

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