Scale factor is always (new/original)
so it depends which rectangle came first. if it started as large and was dilated to the smaller one, then the ratio is (.5/2.5) which simplifies to 1/5 or 0.2.
Let x =lenght, y = width, and z =height
<span>The volume of the box is equal to V = xyz </span>
<span>Subject to the surface area </span>
<span>S = 2xy + 2xz + 2yz = 64 </span>
<span>= 2(xy + xz + yz) </span>
<span>= 2[xy + x(64/xy) + y(64/xy)] </span>
<span>S(x,y)= 2(xy + 64/y + 64/x) </span>
<span>Then </span>
<span>Mx(x, y) = y = 64/x^2 </span>
<span>My(x, y) = x = 64/y^2 </span>
<span>y^2 = 64/x </span>
<span>(64/x^2)^2 = 64 </span>
<span>4096/x^4 = 64/x </span>
<span>x^3 = 4096/64 </span>
<span>x^3 = 64 </span>
<span>x = 4 </span>
<span>y = 64/x^2 </span>
<span>y = 4 </span>
<span>z= 64/yx </span>
<span>z= 64/16 </span>
<span>z = 4 </span>
<span>Therefor the dimensions are cube 4.</span>
Answer:
Part A : E = 35h + 200
Part B : The per hour charges of the technician is $35/hour.
Step-by-step explanation:
The technician observes that his earnings are a linear function of the number of hours he works during the month. The technician finds that when he works 55 hours during the month, he earns $2,125 and when he works 30 hours, he earns $1,250
.
If we consider the number of hours that he works in a month is h and the amount he earns in dollars is E, then (30,1250) and (55,2125) are the two ordered pairs.
Part A : Therefore, the linear function to model the relationship between the number of hours worked and the money earned will be

⇒ E - 2125 = 35(h - 55)
⇒ E - 2125 = 35h - 1925
⇒ E = 35h + 200
Part B : The equation above is in the slope-intercept form and the slope is 35 which means that the per hour charge of the technician is $35/hour. (Answer)
we conclude that if the scale factor from S to M is 3/2, then the scale factor from M to S is 2/4.
<h3>
</h3><h3>What is the scale factor from M to S?</h3>
Suppose we have a figure S. If we apply a stretch of scale factor K to our figure S, we can say that all the dimensions of figure S are multiplied by K.
So, if S represents the length of a bar, then after the stretch we will get a bar of length M, such that:
M = S*K
If that scale factor is 3/2, then we have the case of the problem:
M = (3/2)*S
We can isolate S in the above relation:
(2/3)*M = S
Now we have an equation (similar to the first one) that says that the scale factor from M to S is 2/3.
Then we conclude that if the scale factor from S to M is 3/2, then the scale factor from M to S is 2/4.
If you want to learn more about scale factors:
brainly.com/question/25722260
#SPJ1
<h3><u>Ⲁⲛ⳽ⲱⲉⲅ</u><u>:</u></h3>

<h3><u>Ⲋⲟⳑⳙⲧⳕⲟⲛ:</u></h3>
Here, we area provided a cone with:
- Radius = 48m
- Height = 68 m
We have to find the volume of the cone in feet³, and we are given that 1m = 3.2808ft
<h3><u>Ⳙ⳽ⲓⲛⳋ ⳨ⲟⲅⲙⳙ</u><u>ⳑɑ</u><u>:</u></h3>
The volume of a cone is equal to one third of the volume of a cylinder having the same base radius and height ,i.e:

<u>Therefore</u><u>,</u><u> </u><u>Volume:</u>





![\implies\quad \tt { V = 163,983.36 \times (3.2808)^3 \qquad\quad\bigg[ As, \: 1m = 3.2808ft\bigg]}](https://tex.z-dn.net/?f=%20%5Cimplies%5Cquad%20%5Ctt%20%7B%20V%20%3D%20163%2C983.36%20%5Ctimes%20%283.2808%29%5E3%20%5Cqquad%5Cquad%5Cbigg%5B%20As%2C%20%5C%3A%201m%20%3D%203.2808ft%5Cbigg%5D%7D)


ㅤㅤㅤ~<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u>,</u><u> </u><u>the </u><u>volume </u><u>of </u><u>given </u><u>cone </u><u>is </u><u>5,790,806.5</u><u> </u><u>f</u><u>t</u><u>³</u><u>.</u>