Answer:
3 and 6
Step-by-step explanation:
GCF's or greatest common factors of numbers 1 to 8
1 : 1
2 : 1, 2
3: 1 , 3
4 : 1, 2, 4
5 : 1, 5
6 : 1, 2, 3, 6
7 : 1, 7
8 : 1, 2, 4, 8
3 and 6 have 3 as their GCF
To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
End behavior: f. As x -> 2, f(x) -> ∞; As x -> ∞, f(x) -> -∞
x-intercept: a. (3, 0)
Range: p. (-∞, ∞)
The range is the set of all possible y-values
Asymptote: x = 2
Transformation: l. right 2
with respect to the next parent function:
Domain: g. x > 2
The domain is the set of all possible x-values
Where’s the rest of the info??
