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Bas_tet [7]
3 years ago
10

Which of the following statements demonstrates the associative property of multiplication?

Mathematics
2 answers:
Nata [24]3 years ago
6 0
<span>associative property of multiplication

answer
</span><span>4 ∙ (3 ∙ 6) = (4 ∙ 3) ∙ 6 </span>
Serggg [28]3 years ago
4 0
The associative property<span> states that no matter how numbers are grouped you can expect the same result with addition and multiplication.

Looking at these, the only one that changes how numbers are grouped, not placed, is A, your answer.</span>
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If AB = 4 centimeters, which is closest to BC?
Misha Larkins [42]

Answer:

The correct answer AC = 11.52

Step-by-step explanation:

From the figure attached with this answer shows the triangle ABC.

BC=4 centimeters, m angle B=m angle c, and m angle a = 20 degrees

To find AC

From the figure we can see that D is the mid point and AD⊥BC

Then BD = CD = 4/2 = 2 cm

<BAD = 10° and <CAD = 10°

By using trigonometric ratio,

sin 10 = CD/AC = 2/AC

AC = 2/sin 10 = 2/0.1736 = 11.52

Therefore the value of AC = 11.52 cm

4 0
3 years ago
Read 2 more answers
Can someone find the area? ILL LOVE YOU, LITERALLY. Love you ✌
pogonyaev

Answer:

12 units²

Step-by-step explanation:

ABCD is a parallelogram.

The area (A) of a parallelogram is calculated as

A = bh ( b is the base and h the perpendicular height )

Here b = 12 and h = 1, thus

A = 12 × 1 = 12 units²

7 0
3 years ago
What is the decimals of
I am Lyosha [343]

Answer:

2

Step-by-step explanation:

The answer is 2

7 0
2 years ago
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What is the average rate of change for the sequence shown below?
zmey [24]
I believe your answer is required in Rise/Run form.

Rise is -1 and Run is +2
so
-1/2
8 0
3 years ago
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Which is the solution to the following equation?<br> 4x^2-12x+9=5
Scilla [17]
We assume that
if xy=0
x and y=0

first make it equal to zero

minus 5 on both sides
4x^2-12x+4=0
undistribute 4 for ease
4(x^2-3x+1)=0
since 4 does not equal zero, and the only thing that will get it to zero is 0,
x^2-3x+1=0
use quadratic equation

if you hahve
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}
1x^2-3x+1=0
a=1
b=-3
c=1

x=\frac{-(-3)+/- \sqrt{(-3)^{2}-4(1)(1)} }{2(1)}
x=\frac{3+/- \sqrt{9-4} }{2}
x=\frac{3+/- \sqrt{5} }{2}
x=\frac{3+ \sqrt{5} }{2} or \frac{3- \sqrt{5} }{2}


aprox
x=2.61803 or 0.381966


7 0
3 years ago
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