Answer:
10
Step-by-step explanation:
Ground level is where h = 0, so solve the equation ...
h(x) = 0
-5(x -4)^2 +180 = 0 . . . . substitute for h(x)
(x -4)^2 = 36 . . . . . . . . . . divide by -5, add 36
x -4 = 6 . . . . . . . . . . . . . . positive square root*
x = 10 . . . . . . add 4
The object will hit the ground 10 seconds after launch.
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* The negative square root also gives an answer that satisfies the equation, but is not in the practical domain. That answer would be x = -2. The equation is only useful for time at and after the launch time: x ≥ 0.
Since this equation is already in standard form, there is no need to convert it. Standard form is Ax + By = C. In this equation, 7 = A, 3 = B, and 10 = C. From standard form, Ax + By = C equals negative A over B.
7x + 3y = 10
↓
Then you'd simplify.
The slope cannot be simplified any more, so this would be the final answer.
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<em>- Marlon Nunez</em>
Answer:
the answer is B
Step-by-step explanation:
Just estimate ex: 5 x 5 would be 25, so sqrt 22 would be just before the 5.
Answer:
That would be 2/7
Step-by-step explanation:
Using substitution. x^2 +x+1 at 1 is 7
sqrt4 is 2
2/7
15 I may be wrong but If I am please provide more information.
