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nignag [31]
3 years ago
5

What is the solution to.... 12x-7

Mathematics
2 answers:
yan [13]3 years ago
8 0
2 x − 7 = 7 2x-7=7 2x−7=7. Add 7 to both sides. Simplify 7 + 7 7+7 7+7 to 1 4 14 14. Divide both sides by 2.
kakasveta [241]3 years ago
8 0

Answer:

There is no solution to that line because there is only one line which therefore cannot contain any solutions.

Step-by-step explanation:

12x-7 is only one line if there is two lines then there can be a solution because  if the line meets in one location then that place where they meet is the solution.

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5/2x-7=2/4x+14<br><br>a x = -6<br>b x = 6<br>c x = 8<br>d x = 12​
kykrilka [37]
The answer I got was x= 21/2
3 0
2 years ago
Whats the cube root of 216. Please Explain why also.​
aniked [119]
Answer:6
If you were to multiply 6*6*6 you would get 216
6 0
3 years ago
Find the area of the circle with the given radius or diameter. Use pi = 3.14. d = 10 A =
labwork [276]

The formula in computing the area of the circle is:

A = pi (r)^2

Where r = the radius of the circle

Since you are only given the diameter of the circle, you have to solve for its radius. The radius of the circle is half its diameter. Therefore, the radius of the circle is 5 (10/2).

Now, you substitute the measurements to the formula:

A = 3.14 (5)^2

A = 3.14 (25)

A = 78.5 sq. units

5 0
3 years ago
Read 2 more answers
Help pls. this topic is confusing for me
Leya [2.2K]

Answer:

My brother took this test and said it was 35. Im not sure but try it

Step-by-step explanation:

3 0
3 years ago
Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the
Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million)     Number of companies

25 up to 35                                                    4

35 up to 45                                                    19

45 up to 55                                                    27

55 up to 65                                                    16

65 up to 75                                                     9

TOTAL                                                            75

Let's find the probabilities first:

P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}

For 35 up to 45

P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}

For 45 up to 55

P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}

For 55 up to 65

P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}

For 65 up to 75

P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}

Chi-Square Table can be computed as follows:

Expense   No of   Probabilities(P)  Expe                (O-E)^2   \dfrac{(O-E)^2}{E}

             compa                                 cted E (n*p)

             nies (O)  

25-35           4      0.0612    75*0.0612 = 4.59        0.3481       0.0758

35-45           19     0.2218   75*0.2218 = 16.635     5.5932       0.3362

45-55           27     0.3568   75*0.3568 = 26.76     0.0576      0.021

55-65           16      0.2552   75*0.2552 = 19.14      9.8596      0.5151

65-75           9      0.0839     75*0.0839 = 6.2925   7.331         1.1650

                                                                                           \sum \dfrac{(O-E)^2}{E}= 2.0492                                                                                                      

Using the Chi-square formula:

X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square  \ X^2 = 2.0942

Null hypothesis:

H_o: \text{The population of advertising expenses follows a normal distribution}

Alternative hypothesis:  

H_a: \text{The population of advertising expenses does not follows a normal distribution}

Assume that:

\alpha = 0.02

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from X^2 = 11.667

Decision rule: To reject H_o  \  if \  X^2  test statistics is greater than X^2 tabulated.

Conclusion: Since X^2 = 2.0942 is less than critical value 11.667. Then we fail to reject H_o

6 0
3 years ago
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