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levacccp [35]
3 years ago
11

The displacement s(m) of a jogger from a

Mathematics
1 answer:
maxonik [38]3 years ago
3 0

Answer:

4m/s

Step-by-step explanation:

Velocity = ds/dt

= (change in displacement) ÷ (change in time)

= slope of the function

= 4

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A bottlenose dolphin is 96 inches long. There are 12 inches in 1 foot.
algol [13]

Answer: The answer is 7 feet or foot because 96 divied by 12 is 7

8 0
4 years ago
Yasmin purchased 6 heads of cabbage that each weighed 2 and StartFraction 3 over 8 EndFraction pounds. How much did the cabbage
seropon [69]

Answer:

14 and one-fourth pounds

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
Find the value of yy in each equation. Explain how you determined the value of yy.
SOVA2 [1]

Answer:

a) 2

b) 5

c) -1

d) x

Step-by-step explanation:

We know the properties of log function as:

1) log(AB) = log(A) + log(B)

2) \log(\frac{A}{B}) = \log(A)+\log(B)

3) log(aᵇ) = b × log(a)

also,

4) \log_b(a)=\frac{\log(a)}{\log(b)}

Given:

a. y = log₂(2²)

thus, using 3

y = 2log₂(2)

or using 4

y = 2 × \frac{\log(2)}{\log(2)}

or

y = 2 × 1 = 2

b. y = log₂(2⁵)

thus, using 3

y =  5 × log₂(2)

or using 4

y = 5 × \frac{\log(2)}{\log(2)}

or

y = 5 × 1 = 5

c. y = log₂(2⁻¹)

thus, using 3

y =  -1 × log₂(2)

or using 4

y = -1 × \frac{\log(2)}{\log(2)}

or

y = -1 × 1 = -1

d. y = log₂(2ˣ)

thus, using 3

y =  x × log₂(2)

or using 4

y = x × \frac{\log(2)}{\log(2)}

or

y = x × 1 = x

4 0
4 years ago
Step by step
Damm [24]

Answer:

6x+1<9-2x

6x+2x<9-1

8x<8

x<1

2x-1 ≤ 5x+20

2x-5x≤20+1

-3x≤21

x≥-7

3-(2x-7) ≤ 34-6x

3-2x+7 ≤ 34-6x

-2x+6x ≤ 34-3-7

4x ≤ 24

x ≤ 6

6 0
3 years ago
Question 1: Identify the zeros of the function f(x) = 4x2 − 8x − 1 using the Quadratic Formula. Answers: -1/2 + sqaureroot 5, 1/
Lelechka [254]

Answer:

1.  1/2 +/-√5

2.  1 +/-  i √6/2.

Step-by-step explanation:

1.  f(x) = 4x^2 - 8x - 1

x = [-(-8) +/-√((-8)^2 - 4*4*-1)] / (2*4)

x =[ 8 +/- √80] / 8

= 1 +/- 4√5/8

= 1 +/- √5/2

= 1/2 +/-√5

2. By a similar method the zeros of the the second equation are:

x = [-(-4) +/- √((-4)^2 - 4*2*5)]  / 4

= 4 +/- √(16 - 40) / 4

= 1 +/- √(-24)/4

= 1 +/- i  √6 * 2 / 4

= 1 +/-  i √6/2.

3 0
4 years ago
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