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lesya692 [45]
3 years ago
8

Suppose the goal for mr. Luockwoods class had been 250 cans. Then 550 cans would have been what percent of the goal?

Mathematics
1 answer:
mr_godi [17]3 years ago
3 0

Answer:

220%

Step-by-step explanation:

To find the percent divide the amout collected (550) by the goal (250)

550/250 = 2.2; convert to a %...220%

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A metal worker has several 1-kilogram bars of a metal alloy that contain 23% copper and several 1-kilogram bars that contain 79%
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Answer:

30 each of 23% bars and 18 each of 79% bars

Step-by-step explanation:

If x is the number of 1 kg 23% copper bars, and y is the number of 1 kg 79% copper bars, then:

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Substituting and solving:

0.23x + 0.79(48-x) = 0.44(48)

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You need 30 each of 23% bars and 18 each of 79% bars.

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2x+2\geq 0

Step-by-step explanation:

Given:

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