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Vikki [24]
2 years ago
14

A and B start walking in the same direction at the same time around a circular park of diameter 4200 m. If A walks 10 m more tha

n B in every minute with a speed of 5 km per hour, then they meet each other next time after A makes................ rounds. (ii) 8 (i) 7 (iii) 9 (iv) 10​
Physics
1 answer:
Liono4ka [1.6K]2 years ago
6 0

Answer:

Va = 5000 m / 3600 s = 1.39 m/s

(Va - Vb) 60 = 10

Vb = Va - .167 = 1.22 m/s

(Va - Vb) T = 4200 Π      where T is time for A to complete 1 more lap

.17 T = 4200 Π

T = 24700 Π  time for A to again catch B

N = 1.39 * 24700 Answer:

Va = 5000 m / 3600 s = 1.39 m/s

(Va - Vb) 60 = 10

Vb = Va - .167 = 1.22 m/s

(Va - Vb) T = 4200 Π      where T is time for A to complete 1 more lap

.17 T = 4200 Π

T = 24700 Π  time for A to again catch B

N = 1.39 * 24700 Π / (4200 Π) = 8.2   laps

A will make 8 but not 9 rounds before catching B

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Answer:

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Explanation:

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where,

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Therefore,

E = (400\ kg)(9.81\ m/s^2)(500000\ m)-\frac{1}{2} (400\ kg)(1600\ m/s)^2\\E = 1.962\ x\ 10^9\ J - 0.512\ x\ 10^9\ J

<u>E = 1.45 x 10⁹ J = 1.45 GJ</u>

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3 years ago
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3 years ago
An object is moving with a constant velocity of 278 m/s. How long will it take it to travel 7500 m, using the formula Delta X=Vt
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D.

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