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shusha [124]
2 years ago
8

What is the momentum of a two-particle system

Physics
1 answer:
Harlamova29_29 [7]2 years ago
8 0

Answer:

-67,500 kgm/s

Explanation:

1300 * 20 + 1100 * (-85) = -67,500 kgm/s

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An internal combustion engine uses fuel, of energy content 44.4 MJ/kg, at a rate of 5 kg/h. If the efficiency is 28%, determine
Fudgin [204]
Efficiency =  Power Output / Power Input

Power Input = Rate of Energy input = 44.4 MJ/kg * 5 kg/h

 = 222 MJ/h

But 1 hour = 3600seconds

222 MJ/h = 222 MJ/3600s =  0.061667 MW              J/s = Watts

Power input = 0.061667 MW = 61 667 W

From  Efficiency =  Power Output / Power Input

   28% =  Power Output / 61667

   Power Output = 0.28 * 61667

   Power Output = 17266.76 W
 
  Power Output = 17 267 W

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Rate of heat Rejection = 44 400 W.


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8_murik_8 [283]

Answer:

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3 0
2 years ago
Which of kepler’s laws explains why the sun has a slightly larger angular diameter in january than in july?
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7 0
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viktelen [127]
Hey mate
Here is your answer
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