Answer:

Explanation:
According to given:
- molecular mass of glycerin,

- molecular mass of water,

- ∵Density of water is

- ∴mass of water in 316 mL,

- mass of glycerin,

- pressure of mixture,

- temperature of mixture,

<em>Upon the formation of solution the vapour pressure will be reduced since we have one component of solution as non-volatile.</em>
<u>moles of water in the given quantity:</u>



<u>moles of glycerin in the given quantity:</u>



<u>Now the mole fraction of water:</u>



<em>Since glycerin is non-volatile in nature so the vapor pressure of the resulting solution will be due to water only.</em>



Answer:
I think so but i could be wrong..
Explanation:
The maximum displacement angle of the bob is 13⁰.
The given parameters;
- <em>Length of the pendulum, L = 1.25 m</em>
- <em>Initial velocity of the bob, v = 0.8 m/s</em>
The maximum displacement of the bob is calculated by applying the principle of conservation of energy;

The maximum displacement angle is calculated as follows;

Thus, the maximum displacement angle of the bob is 13⁰.
Learn more here:brainly.com/question/13981780
Speed = distance / time
3.4cm / 0.1s = 34 cm/sec