<u>ANSWER TO PART A</u>
The given triangle has vertices 
The mapping for rotation through
counterclockwise has the mapping

Therefore



We plot all this point and connect them with straight lines.
ANSWER TO PART B
For a reflection across the y-axis we negate the x coordinates.
The mapping is

Therefore



We plot all this point and connect them with straight lines.
See graph in attachment
Answer:
x = 12.99
Step-by-step explanation:
Tan(33) = 
Tan(33) * 20 = x
12.99 = x
Hope this helps!
Think if you had 7/12 of a pie witch is 7 tiny piece opposed to 1 huge piece