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Musya8 [376]
3 years ago
11

In ΔBCD, the measure of ∠D=90°, the measure of ∠C=42°, and CD = 7.5 feet. Find the length of DB to the nearest tenth of a foot.

Mathematics
1 answer:
Whitepunk [10]3 years ago
4 0

We have been given that in ΔBCD, the measure of ∠D=90°, the measure of ∠C=42°, and CD = 7.5 feet. We are asked to find the length of DB to nearest tenth of foot.

First of all, we will draw a right triangle using our given information.

We can see from the attachment that DB is opposite side to angle C and CD is adjacent side to angle.

We know that tangent relates opposite side of right triangle to adjacent side of right triangle.

\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}

\text{tan}(\angle C)=\frac{DB}{CD}

\text{tan}(42^{\circ})=\frac{DB}{7.5}

7.5\cdot\text{tan}(42^{\circ})=\frac{DB}{7.5}\cdot 7.5

7.5\cdot\text{tan}(42^{\circ})=DB

7.5\cdot0.900404044298=DB

DB=7.5\cdot0.900404044298

DB=6.753030332235\approx 6.8

Therefore, the length of DB is approximately 6.8 feet.

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Step-by-step explanation:

A reflection about the x-axis has the rule

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Solving the previous equations (1) and (2) gives

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4 0
3 years ago
Pls help! Asap brainliest to helpful answers
riadik2000 [5.3K]

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125

Step-by-step explanation:

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Can someone find the area? ILL LOVE YOU, LITERALLY. Love you ✌
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Answer:

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Step-by-step explanation:

ABCD is a parallelogram.

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