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iris [78.8K]
3 years ago
10

There are 30 homes in Neighborhood A. Each year, the number of homes increases by 20%. Just down the road, Neighborhood B has 45

homes. Each year, 3 new homes are built in Neighborhood B.
Part A: Write functions to represent the number of homes in Neighborhood A and Neighborhood B throughout the years. (4 points)
Part B: How many homes does Neighborhood A have after 5 years? How many does Neighborhood B have after the same number of years? (2 points)
Part C: After approximately how many years is the number of homes in Neighborhood A and Neighborhood B the same? Justify your answer mathematically. (4 points)
Mathematics
2 answers:
Grace [21]3 years ago
7 0
Part 1: Neighborhood A: 30(1+0.2) ^1 for one year Neighborhood B: 45+3x Part 2: Neighborhood A: 30(1+0.2) ^5 74.6 approx 75 houses in 5 years Neighborhood B: 45+3(5) 60 houses in 5 years I don't know how to do part C, sorry.
nignag [31]3 years ago
5 0
<span>Part A

</span>f(x)=30∗0.2xand<span>f(x)=45+3x</span><span>
___________________________________________________________

Part B</span>

f(x)=30+0.2(5)f(x)=45+3(5)<span>
Neighborhood A and neighborhood B both have 60 houses after 5 years
</span>
___________________________________________________________

Part C

1 year
A=36
B=48 

2 years
A=42
B=51 

3 years
A=48
B=54

4 years
A = 54
B = 57 

5 years
A = 60
B= 60
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