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stepan [7]
3 years ago
15

Explain how you would separate mixture of nitrogen and oxygen gases

Chemistry
1 answer:
mr Goodwill [35]3 years ago
5 0

Answer:

<h2>Cool the mixture to -200 degree Celsius. both gases turn their state to liquids. they are then separated using fractional distillation where as the temperature is increased, nitrogen is first collected because it has the lowest boiling point</h2>
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Because the orientation of the Earth changes throughout the year, meaning certain stars are only visible at certain times.
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Can a tiny organism found in a cave help fight human disease? Explain?
frosja888 [35]

Answer:

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8 0
3 years ago
Suppose a current of 0.860A flows through a copper wire for 5.0 minutes. Calculate how many moles of electrons travel through th
denpristay [2]

Answer:

2.7×10⁻³ mole

Explanation:

Applying

Q = it.............. Equation 1

Where Q = amount of charge, i = current, t = time

From the question,

Given: i = 0.860 A, t = 5 minutes = (5×60) seconds = 300 seconds

Subsitute these values into equation 1

Q = (0.860×300)

Q = 258 C

If one mole of electron has a charge of 96500 C

Then, x mole of electron will have a charge of 258 C

1 mole ⇒ 96500 C

X moles ⇒ 258 C

Solve for X

X = (258×1)/96500

X = 2.7×10⁻³ mole

7 0
3 years ago
When 38.1 grams of a certain metal at a temperature of 90.0°C is added to 100.0mL of water at a temperature of 17.6°C in a perfe
MakcuM [25]

Answer:

a. qm = 627.3 J

b. qw = 627.3 J

c. C₂ = 227.4 J/kg.°C

Explanation:

a.

Since, the calorimeter is completely insulated. Therefore,

Heat Lost by Metal = Heat Gained by water

qm = qw

qm = m₁C₁ΔT₁

where,

qm = heat lost by metal = ?

m₁ = mass of water = (density)(volume) = (1000 kg/m³)(100 mL)(10⁻⁶ m³/1 mL)

m₁ = 0.1 kg

C₁ = specific heat capacity of water = 4182 J/kg.°C

ΔT₁ = Change in Temperature of Water = 19.1°C - 17.6°C = 1.5°C

Therefore,

qm = (0.1 kg)(4182 J/kg.°C)(1.5°C)

<u>qm = 627.3 J</u>

<u></u>

b.

Since,

qm = qw

<u>qw = 627.3 J</u>

<u></u>

c.

qm = m₂C₂ΔT₂

where,

m₂ = mass of metal = 38.1 g = 0.0381 kg

C₂ = specific heat capacity of metal = ?

ΔT₂ = Change in Temperature of metal = 90°C - 17.6°C = 72.4°C

Therefore,

627.3 J = (0.0381 kg)(C₂)(72.4°C)

(627.3 J)/(0.0381 kg)(72.4°C) = C₂

<u>C₂ = 227.4 J/kg.°C</u>

6 0
3 years ago
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