Explanation:
![3CO(g)+Fe_2O_3(s)\rightarrow 2Fe(s)+3CO_2(g)](https://tex.z-dn.net/?f=3CO%28g%29%2BFe_2O_3%28s%29%5Crightarrow%202Fe%28s%29%2B3CO_2%28g%29)
1)Mass of CO when 210.3 g of Fe produced.
Number of moles of
in 210.3 g=
![\frac{\text{Given mass of Fe}}{\text{Molar mass of Fe}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BGiven%20mass%20of%20Fe%7D%7D%7B%5Ctext%7BMolar%20mass%20of%20Fe%7D%7D)
![=\frac{210.3}{55.84 g/mol}=3.76 mol](https://tex.z-dn.net/?f=%3D%5Cfrac%7B210.3%7D%7B55.84%20g%2Fmol%7D%3D3.76%20mol)
According to reaction, 2 moles of Fe are obtained from 3 moles of CO, then 3.76 moles of Fe will be obtained from :
of CO that is 5.64 moles.
Mass of CO in 5.64 moles =
![\text{Number of moles}\times \text{molar mass of CO}=5.46\times 28 g/mol=157.92 g](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%5Ctimes%20%5Ctext%7Bmolar%20mass%20of%20CO%7D%3D5.46%5Ctimes%2028%20g%2Fmol%3D157.92%20g)
2)Mass of CO when 209.7 g of Fe produced.
Number of moles of
in 209.7 g=
![\frac{\text{Given mass of Fe}}{\text{Molar mass of Fe}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BGiven%20mass%20of%20Fe%7D%7D%7B%5Ctext%7BMolar%20mass%20of%20Fe%7D%7D)
![=\frac{209.7}{55.84 g/mol}=3.75 mol](https://tex.z-dn.net/?f=%3D%5Cfrac%7B209.7%7D%7B55.84%20g%2Fmol%7D%3D3.75%20mol)
According to reaction, 2 moles of Fe are obtained from 3 moles of CO, then 3.75 moles of Fe will be obtained from :
of CO that is 5.625 moles.
Mass of CO in 5.625 moles =
![\text{Number of moles}\times \text{molar mass of CO}=5.625\times 28 g/mol=157.5 g](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%5Ctimes%20%5Ctext%7Bmolar%20mass%20of%20CO%7D%3D5.625%5Ctimes%2028%20g%2Fmol%3D157.5%20g)
Answer:
Phosphorus
Explanation:
A group is a vertical column on the periodic table.
A period is a horizontal row on the periodic table.
2Na+MGF2=2NAF+MG
I hope that's right :)
MW of gas : 124.12 g/mol
<h3>Further explanation </h3>
Density is a quantity derived from the mass and volume
Density is the ratio of mass per unit volume
With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of density
The unit of density can be expressed in g/cm³ or kg/m³
Density formula:
![\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7B%5Crho%20~%20%3D%20~%20%5Cfrac%20%7Bm%7D%20%7BV%7D%7D%7D%7D)
ρ = density
m = mass
v = volume
glass vessel wieight = 50 g
glass vessel + liquid = 148 ⇒ liquid = 148 - 50 =98 g
volume of glass vessel :
![\tt V=\dfrac{m}{\rho}=\dfrac{98}{0.989}=99.1~ml](https://tex.z-dn.net/?f=%5Ctt%20V%3D%5Cdfrac%7Bm%7D%7B%5Crho%7D%3D%5Cdfrac%7B98%7D%7B0.989%7D%3D99.1~ml)
An ideal gas :
m = 50.5 - 50 = 0.5 g
P = 760 mmHg = 1 atm
T = 300 K
![\tt PV=\dfrac{mass(m)}{MW}.RT\\\\MW=\dfrac{m.RT}{PV}\\\\Mw=\dfrac{0.5\times 0.082\times 300}{1\times 0.0991}=124.12~g/mol](https://tex.z-dn.net/?f=%5Ctt%20PV%3D%5Cdfrac%7Bmass%28m%29%7D%7BMW%7D.RT%5C%5C%5C%5CMW%3D%5Cdfrac%7Bm.RT%7D%7BPV%7D%5C%5C%5C%5CMw%3D%5Cdfrac%7B0.5%5Ctimes%200.082%5Ctimes%20300%7D%7B1%5Ctimes%200.0991%7D%3D124.12~g%2Fmol)
Answer: There is no question, but we can calculate a couple of items:
Density of sea water sample = (52.987g-44.317g)/8.5ml
Inorganic content of sample (mostly salts) = (44.599g-44.317g)/(52.987g-44.317g) x 100% = percent inorganics in water sample
Explanation: